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3 years ago

An elevator weighs 1500 Newtons. Calculate how much potential energy it has when it is lived 500 meters in the air.

Physics

1 answer:

avanturin [10]3 years ago

4 0

An elevator has 750,000 J when it is lived 500 meters in the air

Answer: Option D

<u>Explanation:</u>

The expression to find the potential energy completely on the basis of forces that on two objects. It can be written as

$potential\ energy (P . E)=m \times acceleration\ due\ to\ gravity\ (g) \times height (h)$

Where,

m – mass of object

Acceleration due to gravity = $9.8 \mathrm{m} / \mathrm{s}^{2}$

h = 500 meters

Force = 1500 Newton

As we know, according to Newton second law of motion, the force can be expressed in terms of mass and gravity (F= ma). So, the potential energy can be calculated as

$P . E=F \times h=1500(500)=750000 J$

Hence, an elevator has 750,000 J when it is lived 500 meters in the air.

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Answer:

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(b)

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3 years ago

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3 years ago

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A sample of an ideal gas is in a tank of constant volume. The sample absorbs heat energy so that its temperature changes from 33

Anuta_ua [19.1K]

Answer:

$\frac{v_{2}}{v_{1}}=2$ .

Explanation:

The average kinetic energy per molecule of a ideal gas is given by:

$\bar{K}=\frac{3k_{B}T}{2}$

Now, we know that $\bar{K} = (1/2)m\bar{v}^{2}$

Before the absorption we have:

$(1/2)m\bar{v_{1}}^{2}=\frac{3k_{B}T_{1}}{2}$ (1)

After the absorption,

$(1/2)m\bar{v_{2}}^{2}=\frac{3k_{B}T_{2}}{2}$ (2)

If we want the ratio of v2/v1, let's divide the equation (2) by the equation (1)

$\frac{v_{2}^{2}}{v_{1}^{2}}=\frac{T_{2}}{T_{1}}$

$\frac{v_{2}}{v_{1}}=\sqrt{\frac{T_{2}}{T_{1}}}$

$\frac{v_{2}}{v_{1}}=\sqrt{\frac{1340}{335}}$

$\frac{v_{2}}{v_{1}}=\sqrt{4}$

Therefore the ratio will be $\frac{v_{2}}{v_{1}}=2$

I hope it helps you!

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3 years ago

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Karolina [17]

Answer:

The center of mass of the Earth–Moon system is 4.613 × 10⁶ m from center of the Earth.

Explanation:

Let the reference point be the center of the Earth

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Where;

Xcm is the distance from center of the Earth =?

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Xe is the center mass of the Earth = 0

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Xm is the center mass of the moon = 4 × 10⁸ m

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Therefore, the center of mass of the Earth–Moon system is 4.613 × 10⁶ m from center of the Earth.

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A child at the top of a slide has a gravatational store of 1800j what is the childs maximum kinetic store as he slides down expl

Mrac [35]

Answer:

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