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fomenos
3 years ago
9

An elevator weighs 1500 Newtons. Calculate how much potential energy it has when it is lived 500 meters in the air.

Physics
1 answer:
avanturin [10]3 years ago
4 0

An elevator has 750,000 J when it is lived 500 meters in the air

Answer: Option D

<u>Explanation:</u>

The expression to find the potential energy completely on the basis of forces that on two objects. It can be written as

potential\ energy (P . E)=m \times acceleration\ due\ to\ gravity\ (g) \times height (h)

Where,

m – mass of object

Acceleration due to gravity =  9.8 \mathrm{m} / \mathrm{s}^{2}

h = 500 meters

Force = 1500 Newton

As we know, according to Newton second law of motion, the force can be expressed in terms of mass and gravity (F= ma). So, the potential energy can be calculated as

P . E=F \times h=1500(500)=750000 J

Hence, an elevator has 750,000 J when it is lived 500 meters in the air.

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Sauron [17]

Answer:

(a) 45 micro coulomb

(b) 6 micro Coulomb

Explanation:

C = 3 micro Farad = 3 x 10^-6 Farad

V = 15 V

(a) q = C x V

where, q be the charge.

q = 3 x 10^-6 x 15 = 45 x 10^-6 C = 45 micro coulomb

(b)

V = 2 V, C = 3 micro Farad = 3 x 10^-6 Farad

q = C x V

where, q be the charge.

q = 3 x 10^-6 x 2 = 6 x 10^-6 C = 6 micro coulomb

6 0
3 years ago
The center of the Milky Way galaxy lies in the direction of the _constellation, aboutlight-years away.
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Answer:

Sagittarius

Explanation:

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5 0
3 years ago
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A sample of an ideal gas is in a tank of constant volume. The sample absorbs heat energy so that its temperature changes from 33
Anuta_ua [19.1K]

Answer:

\frac{v_{2}}{v_{1}}=2.

Explanation:

The average kinetic energy per molecule of a ideal gas is given by:

\bar{K}=\frac{3k_{B}T}{2}

Now, we know that \bar{K} = (1/2)m\bar{v}^{2}

Before the absorption we have:

(1/2)m\bar{v_{1}}^{2}=\frac{3k_{B}T_{1}}{2} (1)

After the absorption,

(1/2)m\bar{v_{2}}^{2}=\frac{3k_{B}T_{2}}{2} (2)

If we want the ratio of v2/v1, let's divide the equation (2) by the equation (1)

\frac{v_{2}^{2}}{v_{1}^{2}}=\frac{T_{2}}{T_{1}}

\frac{v_{2}}{v_{1}}=\sqrt{\frac{T_{2}}{T_{1}}}

\frac{v_{2}}{v_{1}}=\sqrt{\frac{1340}{335}}

\frac{v_{2}}{v_{1}}=\sqrt{4}

Therefore the ratio will be \frac{v_{2}}{v_{1}}=2

I hope it helps you!

4 0
3 years ago
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Karolina [17]

Answer:

The center of mass of the Earth–Moon system is 4.613 × 10⁶ m from center of the Earth.

Explanation:

Let the reference point be the center of the Earth

X_{Cm = \frac{M_eX_e +M_mX_m}{M_e+M_m}

Where;

Xcm is the distance from center of the Earth =?

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Therefore, the center of mass of the Earth–Moon system is 4.613 × 10⁶ m from center of the Earth.

8 0
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Mrac [35]

Answer:

1800 J

Explanation:

Energy is conserved, so the maximum kinetic energy equals the change in gravitational energy.

7 0
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