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4 years ago

Resistance of rod is 1 ohm. It is bent in the form of square. The resistance across adjoint corners is.

Physics

1 answer:

nirvana33 [79]4 years ago

3 0

Answer: The answer to the question is 0.25 ohms

Explanation:

R = u x/A .......1

where u is chosen as the resistivity of

the rod, A is area of the rod and x is

chosen as the length of the rod.

Let R* be the resistance of the

lengths of the rod across the adjoints

Then R* = u1/4.......2

Comparing equation 1 and 2

R* = 1/4

=0.25ohms

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3 years ago

Master of physics needed

Delicious77 [7]

Hey JayDilla, I get 1/3. Here's how:
Kinetic energy due to linear motion is:
$E_{linear}= \frac{1}{2}mv^2$
where
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The rotational part requires the moment of inertia of a solid cylinder
$I_{cyl} = \frac{1}{2}mr^2$
Then the rotational kinetic energy is
$E_{rot}= \frac{1}{2}I \omega ^2= \frac{1}{4}mr^2 \omega ^2$
Adding the two types of energy and factoring out common terms gives
$\frac{1}{2}mr^2 \omega ^2(1+ \frac{1}{2})$
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4 years ago

Resistance of rod is 1 ohm. It is bent in the form of square. The resistance across adjoint corners is.​

Resistance of rod is 1 ohm. It is bent in the form of square. The resistance across adjoint corners is.