1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gavmur [86]
3 years ago
8

Water is pumped steadily out of a flooded basement at a speed of 5.4 m/s through a uniform hose of radius 0.83 cm. The hose pass

es out through a window to a street ditch 3.5 m above the waterline. What is the power of the pump?
Physics
1 answer:
Gala2k [10]3 years ago
6 0

To solve this problem it is necessary to apply the concepts related to the flow as a function of the volume in a certain time, as well as the potential and kinetic energy that act on the pump and the fluid.

The work done would be defined as

\Delta W = \Delta PE + \Delta KE

Where,

PE = Potential Energy

KE = Kinetic Energy

\Delta W = (\Delta m)gh+\frac{1}{2}(\Delta m)v^2

Where,

m = Mass

g = Gravitational energy

h = Height

v = Velocity

Considering power as the change of energy as a function of time we will then have to

P = \frac{\Delta W}{\Delta t}

P = \frac{\Delta m}{\Delta t}(gh+\frac{1}{2}v^2)

The rate of mass flow is,

\frac{\Delta m}{\Delta t} = \rho_w Av

Where,

\rho_w = Density of water

A = Area of the hose \rightarrow A=\pi r^2

The given radius is 0.83cm or 0.83 * 10^{-2}m, so the Area would be

A = \pi (0.83*10^{-2})^2

A = 0.0002164m^2

We have then that,

\frac{\Delta m}{\Delta t} = \rho_w Av

\frac{\Delta m}{\Delta t} = (1000)(0.0002164)(5.4)

\frac{\Delta m}{\Delta t} = 1.16856kg/s

Final the power of the pump would be,

P = \frac{\Delta m}{\Delta t}(gh+\frac{1}{2}v^2)

P = (1.16856)((9.8)(3.5)+\frac{1}{2}5.4^2)

P = 57.1192W

Therefore the power of the pump is 57.11W

You might be interested in
Which structures protect the cell? Check all that apply.
MAXImum [283]

Answer:

cell wall and cell membrane

8 0
2 years ago
Read 2 more answers
Two loudspeakers are about 10 m apart in the front of a large classroom. if either speaker plays a pure tone at a single frequen
Ronch [10]
The observed differences in amplitudes are due to interference between the sound waves. The decrease in amplitude is due to destructive interference of the waves and the increase in amplitude is due to constructive interference.
5 0
3 years ago
Read 2 more answers
Two parallel plates having charges of equal magnitude but opposite sign are separated by 29.0 cm. Each plate has a surface charg
wel

Answer:

(a) E = 3.6 x 10³ N/C = 3.6 KN/C

(b) ΔV = 1044 Volts

(c) K.E = 1.67 x 10⁻¹⁶ J

(d) Vf = 4.47 x 10⁵ m/s

(e) a = 3.45 x 10¹¹ m/s²

(f) F = 5.76 x 10⁻¹⁶ N

(g) E = 3.6 x 10³ N/C = 3.6 KN/C  

(h)  Both values are same in part (h) and (a)

Explanation:

(a)

Electric field between oppositely charged plates is given as follows:

E = σ/ε₀

where,

E = Electric Field Intensity = ?

σ = surface charge density = 32 nC/m² = 3.2 x 10⁻⁸ C/m²

ε₀ = Permittivity of free space = 8.85 x 10⁻¹² C²/N.m²

Therefore,

E = (3.2 x 10⁻⁸ C/m²)/(8.85 x 10⁻¹² C²/N.m²)

<u>E = 3.6 x 10³ N/C = 3.6 KN/C</u>

<u></u>

(b)

E = ΔV/r

ΔV = Er

where,

r = distance between plates = 29 cm = 0.29 m

ΔV = Potential Difference = ?

ΔV = (3.6 x 10³)(0.29)

<u>V = 1044 Volts</u>

<u></u>

(c)

Kinetic Energy of Proton = Work done on Proton

K.E = F r

but,  F = E q

K.E = E q r

where,

q = charge on proton = 1.6 x 10⁻¹⁹ C

Therefore,

K.E = (3600 N/C)(1.6 x 10⁻¹⁹ C)(0.29 m)

<u>K.E = 1.67 x 10⁻¹⁶ J</u>

<u></u>

(d)

K.E = (1/2)m(Vf² - Vi²)

where,

m = mass of proton = 1.67 x 10⁻²⁷ kg

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s

Therefore,

1.67 x 10⁻¹⁶ J = (1/2)(1.67 x 10⁻²⁷ kg)(Vf² - (0 m/s)²]

Vf² = (1.67 x 10⁻¹⁶ J)(2)/(1.67 x 10⁻²⁷ kg)

Vf = √(20 x 10¹⁰ m²/s²)

<u>Vf = 4.47 x 10⁵ m/s</u>

<u></u>

(e)

2as = Vf² - Vi²

2(a)(0.29 m) = (4.47 x 10⁵ m/s)² - (0 m/s)²

a = (20 x 10¹⁰ m²/s²)/0.58 m

<u>a = 3.45 x 10¹¹ m/s²</u>

<u></u>

(f)

F = ma

F = (1.67 x 10⁻²⁷ kg)(3.45 x 10¹¹ m/s²)

<u>F = 5.76 x 10⁻¹⁶ N</u>

<u></u>

(g)

E = F/q

E = (5.76 x 10⁻¹⁶ N)/(1.6 x 10⁻¹⁹ C)

<u>E = 3.6 x 10³ N/C = 3.6 KN/C</u>

<u></u>

(h)

<u>Both values are same in part (h) and (a)</u>

7 0
3 years ago
Name this from taco bell and get brainlest answer :)
lys-0071 [83]
There’s nothing! No pictures
5 0
3 years ago
Read 2 more answers
A cube with sides of area 18 cm^2 contains a 6.0 nanoCoulomb charge. Find the flux of the electric field through the surface of
Vanyuwa [196]

Answer:

The flux of the electric field  is 677.6 Nm²/C

Explanation:

Given that,

Area = 18 cm²

Charge = 6.0 nC

We need to calculate the flux of the electric field

Using Gauss's law

\phi=\dfrac{q}{\epsilon_{0}}

Where, q = charge

\epsilon_{0} =permittivity of free space

Put the value into the formula

\phi=\dfrac{6.0\times10^{-9}}{8.854\times10^{-12}}

\phi=677.6\ Nm^2/C

Hence, The flux of the electric field  is 677.6 Nm²/C.

4 0
3 years ago
Other questions:
  • what issues might arise in determining the latent heat of something that sublimes in comparison to something that melts
    7·2 answers
  • A runner makes one lap around a 200m track of 25s. What were the runners average speed and average velocity?
    14·1 answer
  • A car accelerates uniformly from rest to a speed of 56.8 km/h (15.8 m/s) in 10 s. find the distance the car travels during this
    8·1 answer
  • Which of the following is most closely related to an activated complex?
    14·1 answer
  • a wall switch is connected to a wall outlet. A lamp is plugged into the same outlet. You turn the switch on, but the lamp stays
    15·1 answer
  • A −4.00 μC charge sits in static equilibrium in the center of a conducting spherical shell that has an inner radius 3.13 cm and
    7·1 answer
  • Imagine a rock is dropped from the top of a tall building.After 2 seconds of falling the rock is instantaneous speed In approxim
    6·1 answer
  • Which road would exert the LEAST amount of friction on a car?
    14·1 answer
  • Which of the following statements is true? Thunderstorms are not dangerous The eye of a hurricane is the most danger Tornadoes f
    6·1 answer
  • If the mass of an object increases, predict what will happen to the coefficient of sliding friction.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!