Answer:
145 m
Explanation:
Given:
Wavelength (λ) = 2.9 m
we know,
c = f × λ
where,
c = speed of light ; 3.0 x 10⁸ m/s
f = frequency
thus,

substituting the values in the equation we get,

f = 1.03 x 10⁸Hz
Now,
The time period (T) = 
or
T =
= 9.6 x 10⁻⁹ seconds
thus,
the time interval of one pulse = 100T = 9.6 x 10⁻⁷ s
Time between pulses = (100T×10) = 9.6 x 10⁻⁶ s
Now,
For radar to detect the object the pulse must hit the object and come back to the detector.
Hence, the shortest distance will be half the distance travelled by the pulse back and forth.
Distance = speed × time = 3 x 10^8 m/s × 9.6 x 10⁻⁷ s) = 290 m {Back and forth}
Thus, the minimum distance to target =
= 145 m
Like a then it would be A something I guess it goes like that
Answer:
735 J
Explanation:
From the question given above, the following data were obtained:
Weight (W) = 49 N
Height (h) = 15 m
Potential energy =?
Potential energy is simply defined as the product of weight of the object and height to which the object is raised. Mathematically, it is expressed as:
Potential energy = weight × height
With the above formula, we can obtain the potential energy of the coconut as follow:
Weight (W) = 49 N
Height (h) = 15 m
Potential energy =?
Potential energy = weight × height
Potential energy = 49 × 15
Potential energy = 735 J
Thus, the potential energy of the coconut is 735 J