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Alexandra [31]
3 years ago
14

Nothing. i have nothing to say but that. other than that im good. :))))

Engineering
1 answer:
ohaa [14]3 years ago
4 0

Answer:

aw good <3

Explanation:

You might be interested in
Can someone please help!
Setler [38]

Answer:

Ask. Identifying and Researching a Need.

Imagine. Developing Possible Solutions.

Plan. Making a prototype.

Create. Testing and evaluating.

Improve. Modifying and Retesting the Solution

Explanation:

went though pltw

8 0
3 years ago
The van der Waals equation is a modification of the ideal gas equation. What two factors does this equation account for? A. (1)
Liula [17]

Answer:

E

Explanation:

The vander waals equation

(P+n^2a/V^2)(V-nb)=nRT

The factor n^2a/V^2 accounts for the attractive forces between the gases molecules whereas nb accounts for the decrease in volume occupied by the gas. Therefore, correct option would be  E. None of the above have BOTH of the two factors accurately stated

6 0
3 years ago
One of the basic requirements of a servomotor is that it must produce high torque at all: a)Frequencies b)-Voltages c)-Loads d)-
Schach [20]

Answer: D) Speeds

Explanation:

Servomotor is an electromechanical device that contain feedback mechanism.

In servomotor, torque curve basically depicts that a motor can produce the amount of torque accordingly to the operating speed.

Servomotor are able to hold the heavier loads that is why it has ability to produced high torque in all range of speeds.

5 0
3 years ago
What is an isentropic process?
snow_tiger [21]

Answer: Isentropic process is the process in fluids which have a constant entropy.

Explanation: The  isentropic process is considered as the ideal thermodynamical  process and has both adiabatic as well as reversible processes in internal form.This process supports no transfer of heat and  no transformation of matter .The entropy of the provided mass also remains unchanged or consistent.These processes are usually carried out on material on  the efficient device.

5 0
4 years ago
An Ideal gas is being heated in a circular duct as while flowing over an electric heater of 130 kW. The diameter of duct is 500
Assoli18 [71]

Answer: The exit temperature of the gas in deg C is 32^{o}C.

Explanation:

The given data is as follows.

C_{p} = 1000 J/kg K,   R = 500 J/kg K = 0.5 kJ/kg K (as 1 kJ = 1000 J)

P_{1} = 100 kPa,     V_{1} = 15 m^{3}/s

T_{1} = 27^{o}C = (27 + 273) K = 300 K

We know that for an ideal gas the mass flow rate will be calculated as follows.

     P_{1}V_{1} = mRT_{1}

or,         m = \frac{P_{1}V_{1}}{RT_{1}}

                = \frac{100 \times 15}{0.5 \times 300}  

                = 10 kg/s

Now, according to the steady flow energy equation:

mh_{1} + Q = mh_{2} + W

h_{1} + \frac{Q}{m} = h_{2} + \frac{W}{m}

C_{p}T_{1} - \frac{80}{10} = C_{p}T_{2} - \frac{130}{10}

(T_{2} - T_{1})C_{p} = \frac{130 - 80}{10}

(T_{2} - T_{1}) = 5 K

T_{2} = 5 K + 300 K

T_{2} = 305 K

           = (305 K - 273 K)

           = 32^{o}C

Therefore, we can conclude that the exit temperature of the gas in deg C is 32^{o}C.

8 0
4 years ago
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