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likoan [24]
3 years ago
8

Consider the phase change lab what is required to bring about a phase change

Chemistry
2 answers:
alina1380 [7]3 years ago
3 0

Heating or cooling :)

Ivan3 years ago
3 0

Answer: An increase or decrease in energy.

I took the test it said it was right

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Burning gasoline is an _____________ reaction.
rusak2 [61]

Answer:

chemical.............

5 0
3 years ago
Read 2 more answers
Part A
Elden [556K]

Answer:

ΔG° = -5.4 kJ/mol

ΔG = 873.2 J/mol = 0.873 kJ /mol

Explanation:

Step 1: Data given

ΔG (NO2) = 51.84 kJ/mol

ΔG (N2O4)  = 98.28 kJ/mol

Step 2:

ΔG = ΔG° + RT ln Q

⇒with Q = the reaction quatient

⇒with T = the temperature = 298 K

⇒with R = 8.314 J / mol*K

⇒with ΔG° = ΔG° (N2O4) - 2*ΔG°(NO2 )

⇒ ΔG° = 98.28 kJ/mol - 2* 51.84  kJ/mol

⇒ ΔG° = -5.4 kJ/mol

Part B

ΔG =  ΔG° =RT ln Q

⇒with G° = -5.4 kj/mol = -5400 j/mol

⇒ with R = 8.314 J/K*mol

⇒with T = 298 K

⇒with Q = p(N2O4)/ [ p(NO2) ]² = 1.63/0.36² = 12.577

ΔG = -5400 + 8.314 * 298 * ln(12.577)

ΔG = -5400 + 8.314 * 298 * 2.532

ΔG = 873.2 J/mol = 0.873 kJ/mol

3 0
3 years ago
1- Science that deals with the identification and quantification of the components of material systems
Elis [28]

Answer:

Analytical science

Explanation:

7 0
3 years ago
Are all glucose molecules chemically identical?
CaHeK987 [17]

Answer:

starch: A soft white chemical made by all green plants. It’s a relatively long molecule made from linking together a lot of smaller, identical building blocks — all of them glucose, a simple sugar. Plants and animals use glucose as an energy source. Plants store that glucose, in the form of starch, as a reserve supply of energy.

Explanation:

3 0
3 years ago
A bottle of a commercial reagent-grade hydrochloric acid, HCI, has the following
Doss [256]

The volume of concentrated HCl : 2.073 ml

<h3>Further explanation</h3>

Given

37% HCl by mass; density 1.19 g/mL

Required

The volume of concentrated HCl

Solution

Conversion to molarity :

37% x 1.19 g/ml =0.4403 g/ml

g/ml to mol/L :

=0.4403 g/ml x 1000 ml/L : 36.5 g/mol

=12.06 mol/L

or we can use formula :

\tt M=\dfrac{\%\times \rho\times 10}{MM}\\\\M=\dfrac{37\times 1.19\times 10}{36.5}\\\\M=12.06

Dilution formula :

M₁V₁=M₂V₂

12.06 M x V₁ = 0.1 M x 0.25 L

V₁ = 0.0021 L = 2.073 ml

4 0
3 years ago
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