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lbvjy [14]
3 years ago
8

Which term is defined as the ratio of the speed of light in a vacuum to the speed of light in the material it is passing through

?
A. index of refraction
B.index of reflection
C.angle of reflection
D.angle of incidence
Physics
2 answers:
Eddi Din [679]3 years ago
7 0
<span>The ratio of the speed of light in a vacuum to the
speed of light in the material it is passing through
is the index of refraction of that material. (A)</span>
melisa1 [442]3 years ago
6 0

Answer:

index of refraction

Explanation:

A number that represents how refractive a medium; a ratio of the speed of light in a vacuum to the spee of light in a medium (n=c/v). The larger the index of refraction, the slower light travels.

-the larger the index of refraction, the more refractive it is

-materials with a larger refractive index will bend light more

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Three resistors of resistances, R1=10Ω, R2=5Ω, R3=20Ω are connected in a circuit in such way that same amount of current flows t
Nezavi [6.7K]

Answer

Explanation:

As the three resistors are connected in series, the expression to be used for the  

calculation of RT equivalent resistance

is:  

RT = R1 + R2 + R3

We replace the data of the statement in the previous expression and it remains:  

5 10 15 RT + R1 + R2 + R3 + +

We perform the mathematical operations that lead us to the result we are looking for:  

RT - 30Ω

5 0
3 years ago
A baseball player friend of yours wants to determine his pitching speed. You have him stand on a ledge and throw the ball horizo
Alla [95]

Answer:

v_{ox}= 19.6\ m/s

Explanation:

Data provided in the question:

Height above the ground, H= 5.0m

Range of the ball, R= 20 m

Initial horizontal velocity = v_{ox}

Initial vertical velocity= v_{oy}  (Since ball was thrown horizontally only)

Acceleration acting horizontally, a_x = 0 m/s²  [ Since no acceleration acts horizontally) ]

Vertical Acceleration, a_y = 9.8 m/s² (Since only gravity acts on it)

Let 't' be the time taken to reach ground

Therefore, using equations of motion, we have

H= v_{oy}t+\frac{1}{2}a_yt^2

5= (0)t+\frac{1}{2}(9.8)t^2

t= \frac{10}{9.8}=1.02 s

Then using Equations of motion for horizontal motion,

R= v_{ox}t+\frac{1}{2}a_xt^2

20= v_{ox}(1.02)+\frac{1}{2}(0)(1.02)^2

v_{ox}= 19.6\ m/s

4 0
3 years ago
Use the information to answer the following question.
Nostrana [21]

Answer:

The answer is B. :)

Explanation:

5 0
3 years ago
Calculating heat gained or lost requires mass, specific heat, and
Anarel [89]
<span>Calculating heat gained or lost requires mass, specific heat, and

</span><span>c. change in temperature.</span><span>

</span>
6 0
3 years ago
Suppose we have two planets with the same mass, but the radius of the second one is twice the size of the first one. How does th
bogdanovich [222]

The free-fall acceleration on the second planet is one-fourth the value of the first planet.

Calculation:

Consider the mass of planet A to be, M

               the mass of planet B to be, Mₓ = M

               the radius of planet A to be, R₁

               the radius of planet B to be, R₂

The acceleration due to gravity on planet A's surface is given as:

g = GM/R₁²      - (1)

Similarly, the acceleration due to gravity on planet B's surface is given as:

g' = GM/R₂²                           [where, R₂ = 2R₁]

   = GM/4R₁²    -(2)

From equation 1 & 2, we get:

g/g' = GM/R₁² ÷ GM/4R₁²

g/g' = 4/1

Thus we get,

g' = 1/4 g

Therefore, the free-fall acceleration on the second planet is one-fourth the value of the first planet.

Learn more about free-fall here:

<u>brainly.com/question/13299152</u>

#SPJ4

6 0
2 years ago
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