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Naily [24]
3 years ago
12

Consider a single photon with a wavelength of lambda, a frequency of nu, and an energy of E. What is the wavelength, frequency,

and energy of a pulse of light containing 100 of these photons? 0.01 lambda, nu, and 100E 0.01 lambda, 0.01 nu, and 0.01 E 100 lambda, 100 nu, and E 100 lambda, 100 nu, and 100 E lambda, nu, and 100E
Physics
1 answer:
BARSIC [14]3 years ago
5 0

Answer: lambda \lambda, nu \nu, and 100E

Explanation:

The energy E of a photon is given by:

E=h\nu   (1)

Where:

h is the Planck constant

nu is the frequency

On the other hand, we have an expression that relates the frequency of the photn with its wavelength \lambda:

nu=\frac{c}{\lambda} (2) where c is the speed of light

Substituting (2) in (1):

E=h\frac{c}{\lambda}   (3) This is the energy for a single photon

For 100 photons, the energy is:

100E=100(h\frac{c}{\lambda})=100h\nu   (3)

Where the wavelength and the frequency of the light remains constant.

Therefore, the answer is:

\lambda, \nu, and 100E

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A baseball player hits a ball with 400 n of force.how much does the ball exert on the bat
uranmaximum [27]

Answer:

The ball exerts a force of 400 N on the bat.

Explanation:

Given that,

A baseball player hits a ball with 400 N of force.

We need to find the force the ball exert on the bat.

We know that,

According to Newton's third law, when object 1 exerts a force on an object 2, then object 2 will exert a force on object 1 but in opposite direction.

So, the ball exerts a force of 400 N on the bat.

4 0
2 years ago
The specification limits for a product are 8 cm and 10 cm. A process that produces the product has a mean of 9.5 cm and a standa
My name is Ann [436]

Answer:

The value of Cpk is 0.83.

Explanation:

Given that,

Upper specification limits = 10 cm

lower specification limits = 8 cm

Mean = 9.5

Standard deviation = 0.2 cm

We need to calculate the process capability

Using formula of Cpk

Cpk=min(\dfrac{USL-mean}{3\times SD}, \dfrac{mean-LSL}{3\times SD})

Put the value into the formula

Cpk=min(\dfrac{10-9.5}{3\times0.2}, \dfrac{9.5-8}{3\times0.2})

Cpk=min(0.83,2.5)

Cpk=0.83

Hence, The value of Cpk is 0.83.

4 0
2 years ago
What is the temperature of a 3.72 mm cube (e=0.288) that radiates 56.6 W?
blsea [12.9K]

Answer:

The temperature is 2541.799 K

Explanation:

The formula for black body radiation is given by the relation;

Q = eσAT⁴

Where:

Q = Rate of heat transfer 56.6

σ = Stefan-Boltzman constant = 5.67 × 10⁻⁸ W/(m²·k⁴)

A = Surface area of the cube = 6×(3.72 mm)² = 8.3 × 10⁻⁵ m²

e = emissivity = 0.288

T = Temperature

Therefore, we have;

T⁴ = Q/(e×σ×A) = 56.6/(5.67 × 10⁻⁸ × 8.3 × 10⁻⁵ × 0.288) = 4.174 × 10¹⁴ K⁴

T  =  2541.799 K

The temperature = 2541.799 K.

7 0
3 years ago
A tomato of mass 0.18 kg is dropped from a tall bridge. If the tomato has a speed of 11 m/s just before it hits the ground, what
kondor19780726 [428]
The kinetic energy of the tomato is : 

K.E =  1/2 mv^2

K.E = 1/2 x 0.18 kg x 11 m/S^2

K.E = 0.99

Hope this helps
7 0
3 years ago
Stomach acid is a dilute solution of hydrochloric acid (HCl). In this case the word dilute means
vfiekz [6]
I think the correct answer would be that there are a relatively small number of moles of HCl present. Dilute would mean that there are very few solute particles dissolved as compared to the solvent particles in the solution. Hope this helps.
6 0
3 years ago
Read 2 more answers
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