1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Naily [24]
2 years ago
12

Consider a single photon with a wavelength of lambda, a frequency of nu, and an energy of E. What is the wavelength, frequency,

and energy of a pulse of light containing 100 of these photons? 0.01 lambda, nu, and 100E 0.01 lambda, 0.01 nu, and 0.01 E 100 lambda, 100 nu, and E 100 lambda, 100 nu, and 100 E lambda, nu, and 100E
Physics
1 answer:
BARSIC [14]2 years ago
5 0

Answer: lambda \lambda, nu \nu, and 100E

Explanation:

The energy E of a photon is given by:

E=h\nu   (1)

Where:

h is the Planck constant

nu is the frequency

On the other hand, we have an expression that relates the frequency of the photn with its wavelength \lambda:

nu=\frac{c}{\lambda} (2) where c is the speed of light

Substituting (2) in (1):

E=h\frac{c}{\lambda}   (3) This is the energy for a single photon

For 100 photons, the energy is:

100E=100(h\frac{c}{\lambda})=100h\nu   (3)

Where the wavelength and the frequency of the light remains constant.

Therefore, the answer is:

\lambda, \nu, and 100E

You might be interested in
Characteristics of saturn
Tresset [83]

Saturn is a planet in solar system. It's ring is made out of small covered ice particle. It has over 30 moons.

3 0
3 years ago
Read 2 more answers
dopasuj wartości pracy z ramki do przedstawionych sytuacji ,a nastepnie wyraż te prace w dżulach uwaga jedna wartośc pracy nie b
Eduardwww [97]

Answer:

A (samolot) - 200 MJ = 200000000 J

B (dźwig) - 800 kJ = 800000 J

C (podnośnik)-1.6 kJ = 1600 J

Explanation:

Całą część pytania można znaleźć na poniższym schemacie.

Z diagramu załączonego poniżej; mamy

A - samolot lotniczy

B - dźwig

C - podnoszenie ciężarów

Wszyscy to wiemy ;

1kJ = 1000 J

1MJ = 1000000 J

Mamy cztery opcje; i.e 200 MJ, 800 kJ, 1.6 kJ  and 250 mJ

Z czterech opcji można wykluczyć 250 mJ, ponieważ jest to 0,25 J, co przedstawia bardzo niską energię w porównaniu z trzema warunkami pokazanymi na schemacie.

Więc:

A (samolot) - 200 MJ = 200000000 J

B (dźwig) - 800 kJ = 800000 J

C (podnośnik)-1.6 kJ = 1600 J

Największą pracę wykona samolot. Jest tak, ponieważ ma bardzo dużą masę i bardzo dużą prędkość. W związku z tym istnieje potrzeba wytworzenia ogromnej ilości ciepła i energii.

Z drugiej strony żuraw może podnieść ładunek o wiele większy i przewyższa ciężar ciężaru, więc praca wykonywana przez dźwig musi być zdecydowanie większa niż praca ciężarka.

3 0
2 years ago
A box of mass 0.8 kg is placed on an inclined surface that makes an angle 30 above
earnstyle [38]

Answer:

a)    a = 17.1 m / s², b)    F = 3.04 N

Explanation:

This is an exercise of Newton's second law, in this case the selection of the reference system is very important, we have two possibilities

* a reference system with the horizontal x axis, for this selection the normal and the friction force have x and y components

* a reference system with the x axis parallel to the plane, in this case the weight and the applied force have x and y components

We are going to select the second possibility, since it is the most used in inclined plane problems, let's analyze the angle of the applied force (F) it has an angle 10º with respect to the x axis, if we rotate this axis 30º the new angle is

                θ = 10 -30 = -20º

The negative sign indicates that it is in the fourth quadrant. Let's use trigonometry to find the components of the applied force

              sin (-20) = F_{y} / F

              cos (-20) = Fₓ / F

              F_{y} = F sin (-20)

              Fₓ = F cos (-20)

              F_y = 18 sin (-20) = -6.16 N

              Fₓ = 18 cos (-20) = 16.9 N

The decomposition of the weight is the customary

               sin 30 = Wₓ / W

               cos 30 = W_y / W

               Wₓ = W sin 30 = mg sin 30

                W_y = W cos 30 = m g cos 30

                Wₓ = 0.8 9.8 sin 30 = 3.92 N

                 W_y = 0.8 9.8 cos 30 = 6.79 N

Notice that in the case  the angle is measured with respect to the axis y perpendicular to the plane

Now we can write Newton's second law for each axis

X axis

      Fₓ - fr = m a

Y Axis  

      N - F_{y} - Wy = 0

      N =F_{y} + Wy

      N = 6.16 + 6.79

     

They both go to the negative side of the axis and

      N = 12.95 N

The friction force has the formula

        fr = μ N

we substitute

        Fₓ - μ N = m a

        a = (Fₓ - μ N) / m

     

we calculate

       a = (16.9 - 0.25 12.95) / 0.8

       a = 17.1 m / s²

b) now the block slides down with constant speed, therefore the acceleration is zero

ask for the value of the applied force, we will suppose that with the same angle, that is, only its modulus was reduced

       Newton's law for the x axis

              Fₓ -fr = 0

              Fₓ = fr

              F cos 20 = μ N

              F = μ N / cos 20

we calculate

              F = 0.25 12.95 / cos 20

              F = 3.04 N

this is the force applied at an angle of 10º to the horizontal

3 0
2 years ago
A sprinter explodes out of the starting block with an acceleration of +4.2 m/s2, which she sustains for 0.9 s. Then, her acceler
ad-work [718]

Answer:

a) 3.78 m/s

b) 3.78 m/s

Explanation:

a )From the equations of kinematics   we know that

     Vf - Vi = at

since Initial speed Vi = 0

acceleration = 4.2 m/s2

so we have

     Vf = a t

           = (4.2) (0.9)

         = 3.78 m/s

velocity at t = 0.9 s. m/s is 3.78 m/s

b) If the sprinter maintains constant velocity then acceleration becomes zero.

   So velocity is 3.78 m/s

6 0
3 years ago
Please help.
LenKa [72]
Mu wildest guess is c 1500
7 0
3 years ago
Read 2 more answers
Other questions:
  • True or False
    10·1 answer
  • If a car is traveling on the highway at a constant velocity, the force that pushes the car forward must be A. equal to the weigh
    13·1 answer
  • If the net force on an object is in a negative direction, what will the direction of the resulting acceleration be?
    7·1 answer
  • The angle of incidence at a solid/liquid boundary is 59.6a?°, and the index of refraction of the solid is n = 1.55. (a what must
    14·1 answer
  • An earthquake’s epicenter is _____.
    13·2 answers
  • The two most prominent wavelengths in the light emitted by a hydrogen discharge lamp are 656 nm (red) and 486 nm (blue). Light f
    10·1 answer
  • Given that both liquid A and B exert the same amount of pressure .What would be the height of column of liquid A if the density
    7·1 answer
  • How do you make a iPad I can text and stuff and don't understand how
    5·2 answers
  • A wave hits a wall as shown. A brick wall with a green arrow pointing to the wall from below and right at a shallow angle. Anoth
    10·1 answer
  • A loop rests in the plane of a page of textbook while a magnetic field is directed into the page. A clockwise current is induced
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!