Complete question:
At a particular instant, an electron is located at point (P) in a region of space with a uniform magnetic field that is directed vertically and has a magnitude of 3.47 mT. The electron's velocity at that instant is purely horizontal with a magnitude of 2×10⁵ m/s then how long will it take for the particle to pass through point (P) again? Give your answer in nanoseconds.
[<em>Assume that this experiment takes place in deep space so that the effect of gravity is negligible.</em>]
Answer:
The time it will take the particle to pass through point (P) again is 1.639 ns.
Explanation:
F = qvB
Also;

solving this two equations together;

where;
m is the mass of electron = 9.11 x 10⁻³¹ kg
q is the charge of electron = 1.602 x 10⁻¹⁹ C
B is the strength of the magnetic field = 3.47 x 10⁻³ T
substitute these values and solve for t

Therefore, the time it will take the particle to pass through point (P) again is 1.639 ns.
Answer:
a. 
b. 
Explanation:


, 
radius earth = 6371 km
mass earth = 5,972*10^24 kg
a.



b.






Answer:
<u>Toxicity is a quantitative property</u>
Explanation:
- Qualitative property of a object cannot be measured it can just be observed
- Quantitative property of a substance can be measured and be assigned a numerical value .
- <u>The toxicity level of a substance can be measured and be assigned a numeral value </u>
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.