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4 years ago

Calculate the momentum of of a 1,5000 kg car traveling at 6 m/s

Physics

1 answer:

ANEK [815]4 years ago

4 0

Answer: 90000 kgm/s

Explanation:

Given that,

Momentum of car = ?

Mass of car = 1,5000 kg

Velocity of car = 6 m/s

Recall that momentum is the product of mass of the moving object by its velocity

i.e Momentum = mass x velocity

Momentum = 15000kg x 6m/s

= 90000kgm/s

Thus, the momentum of the car is 90000 kgm/s

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How do the three types of boundary's work together to keep the Earth at equilibrium?

Maurinko [17]

There are three types: divergent, convergent, and transform boundaries. I hope this helps.

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3 years ago

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A truck accelerates From being stopped to 18 m/s in 5.5 seconds. A bus accelerates from being stopped to 24 m/s in 6.0 seconds.

Mars2501 [29]

Answer:

The bus

Explanation:

a = (v-u)/t

Where

a = acceleration

v = final velocity

u = initial velocity

t = time taken

For truck to get its acceleration,

a = (18-0)/5.5 = 3.27 ms⁻²

For bus to get its acceleration,

a = (24-0)/6 = 4 ms⁻²

As 4 > 3.27 bus has a greater acceleration.

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3 years ago

The Carson family's pancake recipe uses 2 teaspoons of baking powder for every 1/3 of a teaspoon of salt. How much baking powder

melomori [17]

Answer:

6 teaspoons of baking powder required.

Explanation:

Given that

According to the recipe of pancake,

For every $\frac{1}{3}$ teaspoon of salt, 2 teaspoons of baking baking powder is required.

To find:

How much baking powder will be needed, if 1 teaspoon of salt was used ?

Solution:

This problem can be solved using ratio.

$\frac{1}3$ teaspoon of salt : 2 teaspoons of baking powder

Let us multiply the above ratio with 3.

$\frac{1}{3}\times 3$ teaspoon of salt : 2 $\times$ 3 teaspoons of baking powder

1 teaspoon of salt : 6 teaspoons of baking powder

So, answer is 6 teaspoons of baking powder required.

Also, we can use the unitary method:

$\frac{1}3$ teaspoon of salt needs = 2 teaspoons of baking powder

1 teaspoon of salt needs = $\frac{2}{\frac{1}3}$ teaspoons of baking powder

1 teaspoon of salt needs = 2 $\times$ 3 = 6 teaspoons of baking powder needed

So, the answer is:

6 teaspoons of baking powder required.

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3 years ago

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Your grandmother enjoys creating pottery as a hobby. She uses a potter's wheel, which is a stone disk of radius R-0.520 m and ma

Lesechka [4]

Answer:

0.54454

104.00902 N

Explanation:

m = Mass of wheel = 100 kg

r = Radius = 0.52 m

t = Time taken = 6 seconds

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity

$\alpha$ = Angular acceleration

Mass of inertia is given by

$I=\dfrac{mr^2}{2}\\\Rightarrow I=\dfrac{100\times 0.52^2}{2}\\\Rightarrow I=13.52\ kgm^2$

Angular acceleration is given by

$\alpha=\dfrac{\tau}{I}\\\Rightarrow \alpha=\dfrac{\mu fr}{I}\\\Rightarrow \alpha=\dfrac{\mu 50\times 0.52}{13.52}$

Equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=\omega_i+\dfrac{\mu (-50)\times 0.52}{13.52}t\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{\mu (-50)\times 0.52}{13.52}\times 6\\\Rightarrow 0=6.28318-11.53846\mu\\\Rightarrow \mu=\dfrac{6.28318}{11.53846}\\\Rightarrow \mu=0.54454$

The coefficient of friction is 0.54454

At r = 0.25 m

$\omega_f=\omega_i+\dfrac{0.54454 (-50)\times 0.52}{13.52}6\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{0.54454 f\times 0.25}{13.52}6\\\Rightarrow 2\pi=0.06041f\\\Rightarrow f=\dfrac{2\pi}{0.06041}\\\Rightarrow f=104.00902\ N$

The force needed to stop the wheel is 104.00902 N

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3 years ago

Mixture are the same throughout

Alex787 [66]

Changes. :) I think... Whats your question
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4 years ago

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