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labwork [276]
3 years ago
15

What does the rf value describe on a microscopic level why is this important?

Chemistry
1 answer:
lys-0071 [83]3 years ago
8 0

Answer: The retention factor describes the rate at which a compound migrates on a microscopic level.

The retention factor (Value) serves as a simple measurement of the relative binding of the compound of interest under the experimental conditions.

Retention factor values are used in identification purposes;

• Use to determine the affinity of the solute to the solvent

• Greater retention factor means greater affinity of solute to the solvent

Explanation:

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What gas is measured in an ICE CORE and what is the correlation between that gas and temperature?
PSYCHO15rus [73]

Answer:

Explanation By looking at past concentrations of greenhouse gasses in layers in ice cores, scientists can calculate how modern amounts of carbon dioxide and methane compare to those of the past, and, essentially, compare past concentrations of greenhouse gasses to temperature. Ice coring has been around since the 1950s.n:

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What pressure (in atmospheres) does a gas exert when at 385 mm of Hg?
Westkost [7]
To find out the pressure in atm. You must divide 385 by 760. So pressure in atmospheres equals 385/760.
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4 years ago
Terry, a student, performs a titration. He completes these steps as part of his titration procedure: 1. He cleans and rinses a b
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D

Explanation:

D is the answer because 2 is needed to know

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3 years ago
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Hydrogen is a possible future fuel. However, elemental hydrogen is rare, so it must be obtained from a hydrogen- containing comp
dimulka [17.4K]

Answer:

1.1 × 10² g

Explanation:

First, we will convert 1.0 L to cubic centimeters.

1.0 L × (10³ mL/1 L) × (1 cm³/ 1 mL) = 1.0 × 10³ cm³

The density of water is 1.0 g/cm³. The mass corresponding to 1.0 × 10³ cm³ is:

1.0 × 10³ cm³ × (1.0 g/cm³) = 1.0 × 10³ g

1 mole of water (H₂O) has a mass of 18 g, consisting of 2 g of H and 16 g of O. The mass of Hydrogen in 1.0 × 10³ g of water is:

1.0 × 10³ g H₂O × (2 g H/18 g H₂O) = 1.1 × 10² g

4 0
3 years ago
The complete combustion of a sample of propane produced 2.641 grams of carbon dioxide and 1.442 grams of water as the only produ
ohaa [14]
A general equation for a combustion reaction would be expressed as follows:

CxHy + (x+y/2)O2 = xCO2 + y/2H2O

Propane would obviously would only have carbon and hydrogen in its structure. Assuming a complete combustion, all of the carbon atoms would go to carbon dioxide and all of the hydrogen atoms to water. To determine the empirical, we determine the number of carbon and hydrogen atoms present.

moles C = 2.461 g CO2 ( 1 mol / 44.01 g ) ( 1 mol C / 1 mol CO2 ) = 0.06 mol C

moles H = 1.442 g H2O ( 1 mol / 18.02 g ) ( 2 mol H / 1 mol H ) = 0.16 mol H

Then, we divide the smallest amount to the each mole of the atoms. We do as follows:

C = 0.06 / 0.06 = 1
H = 0.16 / 0.06 = 2.67

Then we multiply a number in order to obtain a whole number ratio between the atoms.

1        CH2.67
2       C2H5.34
3       C3H8   <-------- empirical formula
8 0
3 years ago
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