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Andru [333]
3 years ago
12

What are 5 advantages of wood as a manufacturing or construction​

Engineering
1 answer:
Lapatulllka [165]3 years ago
5 0

Answer:

Wood Enhances Energy Efficiency

Wood has a higher insulation rating than either steel or plastic as a result of its natural cellular structure. This means that homes and buildings require less energy to maintain heating and cooling, plus wood can help regulate humidity levels to a small degree.

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An 18-in.-long titanium alloy rod is subjected to a tensile load of 24,000 lb. If the allowable tensile stress is 60 ksi and the
Vilka [71]

Answer:

Required Diameter = 302.65 inches

Explanation:

We are given;

Allowable tensile stress = 60 ksi

Weight of tensile load = 24,000 lb

Elongation = 0.05 in

Original length = 18 in

We'll need to check the diameters under stress and strain.

Now, we know that the formula for stress is;

Stress = Force/Area

Thus,

Area = Force/stress

So for this stress, area required is;

A_req = 24000/60 = 4000 in²

So let's find the required diameter here.

Area = πd²/4

So, 4000 = πd²/4

(4000 x 4)/π = d²

d² = 5092.96

Required diameter here is;

d = √5092.96

d = 71.36 in

For Strain;

Formula for strain is;

Strain = stress/E

We are given E = 120 ksi

stress = P/A = 24,000/A

strain = elongation/original length = 0.05/18 = 0.00278

Thus;

0.00278 = P/(A•E)

0.00278 = 24000/(120 x A)

Making A the subject to obtain;

A = 24000/(120 x 0.00278)

A_required = 71942 in²

Area = πd²/4

So, 71942 = πd²/4

(71942 x 4)/π = d²

d² = 91599.4

Required diameter here is;

d = √91599.4

d = 302.65 in

The larger diameter is 302.65 inchesand it's therefore the required one.

3 0
4 years ago
Which of the following have the capacity to display formatted data?
sukhopar [10]

Answer:

D.  A and B

Explanation:

1. The method Console.Write() is an overloaded method in a language like C#.

One of its variations could be as follows;

<em>Console.Write(String format, Object a, Object b).</em>

This contains three parameters and will write the text representation of the specified objects to the standard output stream using the information specified by the format specifier. Parameter 1 is <em>format</em> which is a composite format string representing the format specifier. Parameter 2 is <em>a</em>, which is the first object to be written using <em>format. </em>Parameter 3 is b, which is the second object to be written using <em>format</em>.

2. The method Console.WriteLine() has the same characteristics as Console.Write() above, except that it writes the text representation of the specified objects, followed by current line terminator then to the standard output stream using the information specified by the format specifier.

3. Console.WriteFormat() does not exist, at least not in C# or .NET

Therefore, Console.Write() and Console.WriteLine() have the capacity to display formatted data.

<em>Hope this helps!</em>

6 0
3 years ago
An automobile tire with a volume of 0.8 m3 is inflated to a gage pressure of 200 kPa. Calculate the mass of air in the tire if t
saveliy_v [14]

Answer:

2.83 kg

Explanation:

Given:

Volume, V = 0.8 m³

gage pressure, P = 200 kPa

Absolute pressure = gage pressure + Atmospheric pressure

= 200 + 101 = 301 kPa = 301 × 10³ N/m²

Temperature, T = 23° C = 23 + 273 = 296 K

Now,

From the ideal gas equation

PV = mRT

Where,

m is the mass

R is the ideal gas constant = 287 J/Kg K. (for air)

thus,

301 × 10³ × 0.8 = m × 287 × 296

or

m = 2.83 kg

3 0
3 years ago
To convert a whole number to a fraction the number can be written over a denominator of
exis [7]
One

When you convert a whole number into a fraction, you put the whole number as the numerator and the denominator as 1.

Such as 12=12/1 or 5=5/1
7 0
3 years ago
A zener diode exhibits a constant voltage of 5.6 V for currents greater than five times the knee current. IZK is specified to be
8090 [49]

Answer:

The maximum power dissipation of the zener diode 112mV.

Explanation:

The minimum zener current should be:

5 * Iza= 5 * 1=  5 mA.

Since the load current can be at maximum 15 mA, we should select R so that, IL= 15 mA.

A zener current of 5 mA is available, Thus the current should be 20 mA, which leads to,

R = \frac{15 - 5.6}{20 mA} = 470 Ω.

Maximum power dissipated in the diode occours when, IL=0 is

Pmax = 20 * 10^{3} * 5.6 = 112mV.

5 0
4 years ago
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