Answer:
9.82 × 
Hz
Explanation:
De Broglie equation is used to determine the wavelength of a particle (e.g electron) in motion. It is given as:
λ = 
where: λ is the required wavelength of the moving electron, h is the Planck's constant, m is the mass of the particle, v is its speed.
Given that: h = 6.63 ×
Js, m = 2.50 kg, v = 2.70 m/s, the wavelength, λ, can be determined as follows;
λ =
= 
= 
= 9.8222 ×
The wavelength of the object is 9.82 × Hz.
Answer:
COMPLETE QUESTION
A spring stretches by 0.018 m when a 2.8-kg object is suspended from its end. How much mass should be attached to this spring so that its frequency of vibration is f = 3.0 Hz?
Explanation:
Given that,
Extension of spring
x = 0.0208m
Mass attached m = 3.39kg
Additional mass to have a frequency f
Let the additional mass be m
Using Hooke's law
F= kx
Where F = W = mg = 3.39 ×9.81
F = 33.26N
Then,
F = kx
k = F/x
k = 33.26/0.0208
k = 1598.84 N/m
The frequency is given as
f = ½π√k/m
Make m subject of formula
f² = ¼π² •(k/m
4π²f² = k/m
Then, m4π²f² = k
So, m = k/(4π²f²)
So, this is the general formula,
Then let use the frequency above
f = 3Hz
m = 1598.84/(4×π²×3²)
m = 4.5 kg
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Momentum is simply a quantity that measures the impact of a moving body over something is due to the mass it posseses or the velocity with which it is moving.
Mathematically,ut is the product of mass and velocity of a body.
It is represented by capital p...(P)
P=mv
Solution to the problem:
we know P=mv
For mass,eliminate m from the equation,
m=P/v
Put values,
m=5000/5=1000kg
