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alexgriva [62]
4 years ago
8

(i)What mass of carbon dioxide (in kg) is produced upon the complete combustion of

Chemistry
1 answer:
zepelin [54]4 years ago
6 0

Answer:

The answer to your question is:

a) 35211 g of CO2

b) Molarity = 0.03

Explanation:

a)

mass of CO2 = ?

Volume = 18.9 L

density = 0.621 g/ml

Reaction

                C₃H₈    +    5O₂      ⇒     3CO₂     +     4H₂O

Density = mass / volume

mass = density x volume

mass = 0.621 x 18900

mass = 11737 g

MW of C3H8 = 44 g

MW of 3CO2 = 132 g

                         44 g of C3H8  -------------------  132 g of CO2

                     11737 g of C3H8 --------------------   x

                        x = (11737 x 132) / 44

                       x = 35211 g of CO2

b)             H3PO4(aq) + 3NaOH(aq) ---> 3H2O(l) + Na3PO4(aq)

                 22 ml             18.6 ml

                  [?]                  0.11 M

Calculate moles of NaOH

n = M x V

n = 0.11 x 0.0186

n = 0.0020 moles

From the balance reaction

               1 mol of H3PO4 ------------------  3 moles of NaOH

                x                        ------------------   0.0020 moles

               x = (0.002 x 1) / 3

              x = 0.0007  mol of H3PO4

Molarity = 0.0007 / 0.022

Molarity = 0.03

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AURORKA [14]

Answer:

Total numbe of protons and neutrons in a single atom of that element

Explanation:

Hello,

I'll answer the question by filling in the blank spaces

"The atomic mass of an element is equal to the total number of proton and neutron in a particular atom of the element. The atomic mass of an element is equal to the atomic weight. Its mass number one-twelfth of the mass of carbon-12 atom a weighted mass of all naturally occurring isotopes of the elements. Its atomic mass is the average mass of all the naturally occurring isotopes of the element."

The atomic mass of an element is the total number of protons and neutrons in a single atom of that element.

8 0
3 years ago
In two or more complete sentences explain how to balance the chemical equation, KClO3 ⟶ KCl + O2 and include all steps. Write yo
Serggg [28]

Answer:

2KClO3 -------> 2KCl + 3O2

Explanation:

First, in balancing a chemical reaction such as the one given in the question, you should understand that for an equation to be balanced, the number of atoms and ions on both sides of the equation that is the right and left side must be equal. This follows the law of conservation of mass which tells us that matter can neither be created nor destroyed but can be changed into another form.

Next is to begin balancing the equation by identifying and writing down the substances given:

KCl03 ---------> KCl + O2

Next is to count he number of the individual atoms on each side and find out if they are the same on both sides and if not you must follow the next step.

Add a corresponding number and use it to multiply the atoms involved

KClO3 ---------> KCl + O2

Oxygen is 3 on the left side and two on the other side, so we multiply the left hand side by 2 and the right hand side by 3

2KClO3 -----> KCl + 3O2

The potassium and Chlorine are no longer balanced, so you multiply the right had=nd side of KCl by 2.

2KClO3 -----> 2KCl + 3O2

The reactionis herefore balanced as both sides have equal number of atoms and ions.

5 0
4 years ago
When gas particles collide with a surface
sergij07 [2.7K]
The average kinetic energy of a collection of gas particles depends on the temperature of the gas and nothing else.
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3 years ago
Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 1.731.
Amanda [17]

Answer:

The answer to your question is letter c) 6.09 g of sodium and 9.38 g of chlorine.

Explanation:

This problem is solve using rule of three

We know that the proportion Sodium to Chloride is 1 to 1 in sodium chloride, so we have to look for this proportion in the options

AM Sodium = 23 g

AM Chlorine = 35.5 g

                 Sodium                                     Chlorine

           23 g ---------------- 1 mol              35.5 g -------------- 1 mol

       1713.73g -------------    x               2666.6 g -------------    x

          x = 1713.73/23 = 74.51                     x = 2666.6/35.5 = 75.12

    These values are very similar, we have to look for the proportion in the options

a)      6.09g of sodium = 0.26 mol

      4,87 g of chlorine = 0.14 mol           These numbers are not very similar

b) We have 0.26 mol of Na

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c) We have 0.26 mol of Na

                  0.26 mol of Cl                     These numbers are the same, the proportion is 1:1, this is the answer

d) We have 0.26 mol of Na

                   0.36 mol of Cl                    This is not the answer

8 0
3 years ago
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Alona [7]
Yes they will need to worry cause the chemicals could spread in the water making it explode and kill animals and it would be very bad
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