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Ne4ueva [31]
3 years ago
10

What is the force that can cause two pieces of iron to attract each other?

Physics
2 answers:
yulyashka [42]3 years ago
8 0

Is it A ?  Yes !  Two pieces of iron DO always attract each other with equal and opposite gravitational forces, although the forces are so small that we never notice them.

Is it B ?  Yes, it could be.  If at least one of the pieces of iron is magnetized, then they can attract each other with equal and opposite magnetic forces.

Is it C ?  Yes, it could be.  But the pieces of iron would have to be joined by a stretched rubber band.  Then they would attract each other with equal and opposite elastic forces.

Is it D ?  Yes, it could be.  If one of the pieces of iron carries a net electric charge, then they attract each other with equal and opposite electrostatic forces.  

Rudiy273 years ago
6 0

Answer:

B. Magnetic Force

Explanation:

two pieces of irons cannot attract each other unless at least one of them is magnetize. That force is called magnetism.

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Suppose you have two solid bars, both with square cross-sections of 1 cm2. They are both 24.6 cm long, but one is made of copper
vodka [1.7K]

Explanation:

Expression to calculate thermal resistance for iron (R_{I}) is as follows.

             R_{I} = \frac{L_{I}}{k_{I} \times A_{I}}  

where,   L_{I} = length of the iron bar

             k_{I} = thermal conductivity of iron

             A_{I} = Area of cross-section for the iron bar

Thermal resistance for copper (R_{c}) = \frac{L_{c}}{k_{c} \times A_{c}}[/tex]

where,  L_{c} = length of copper bar

             k_{c} = thermal conductivity of copper

            A_{c} = Area of cross-section for the copper bar

Now, expression for the transfer of heat per unit cell is as follows.

           Q = \frac{(100^{o} - 0^{o}}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}

 Putting the given values into the above formula as follows.

       Q = \frac{(100^{o} - 0^{o})}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}

  = \frac{(100^{o} - 0^{o})}{21 \times 10^{-2} m[\frac{1}{73 \times 10^{-4}m^{2}} + \frac{1}{386 \times 10^{-4}m^{2}}}

           = 2.92 Joule

It is known that heat transfer per unit time is equal to the power conducted through the rod. Hence,

                 P = \frac{Q}{T}

Here, T is 1 second so, power conducted is equal to heat transferred.

So,           P = 2.92 watt

Thus, we can conclude that 2.92 watt power will be conducted through the rod when it reaches steady state.

7 0
3 years ago
How can you find the mass of a tissue box?
a_sh-v [17]

Explanation:

To find the volume of a box of Tissue (also known as a rectangular prism) just multiply the area of the base (length times width) by the height. The formula is V = l• w• h.

7 0
2 years ago
1)
Ket [755]

Answer:

1) D

2) A

Explanation:

1) Each group has the same number of valence electrons, which are the outer electrons.

2) Ionic bonds are between a metal and non - metal, the metal being sodium and the non - metal being chlorine.

3 0
3 years ago
Hi Guys.I was just wondering if given two specific heat capacities (In my case copper and water) do you add them both together o
timama [110]

Answer:

yes

Explanation:

using law of HC(heat capacity), which is

  • heat loss=heat gain
  • energy H=MCQ

Where M is mass of substance,C is specific heat capacity, and Q is temperature change

In case of two substance

  • the H = Mc*Cc*Q+Mw*Cw*Q(provided the initial and final temperature are given)

8 0
2 years ago
how do I solve how much time does it take for a satellite moving 15000 miles per hour travel to travel once around the earth 249
iogann1982 [59]

Answer:

The time taken by the satellite to orbit earth at its surface, t = 1.66 hr

Explanation:

Given data,

The velocity of the satellite, v = 15000 miles/hr

The distance of travel, d = 24901 miles,

It is equal to the circumference of earth,

So the time taken by the satellite to orbit earth at its surface,

                           v = d/t

                            t = d/v

Substituting the given values in the above equation,

                            t = 24901 / 15000

                              = 1.66 hr

Hence, the time taken by the satellite to orbit earth at its surface, t = 1.66 hr

3 0
3 years ago
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