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givi [52]
4 years ago
7

Which of the following describes thomsons atomic model?

Physics
1 answer:
Lyrx [107]4 years ago
5 0
The believe that the best answer among the choices provided by the question is a small nucleus with electrons moving around it
Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
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How can you use a ticker tape timer in describing motion graphically?
Bad White [126]
Ticker Tape analysis is a common way of analyzing the motion of the objects to perform in the physics laboratory. A long tape is attached to a moving object and threaded through a device that places a tick upon the tape at regular intervals of time. This ticker tape can also determine if the object is fast or slow. It can also reveal if the object is moving with a constant velocity or accelerating. The changing velocity and acceleration represented by the changing distance between dots in the ticker tape. And also the constant velocity and therefore no acceleration represent the constant distance between dots.

8 0
3 years ago
A ski jumper travels down a slope and leaves
Serhud [2]

Question seems to be missing. Found it on google:

a) How long is the ski jumper airborne?

b) Where does the ski jumper land on the incline?

a) 4.15 s

We start by noticing that:

- The horizontal motion of the skier is a uniform motion, with constant velocity

v_x = 28 m/s

and the distance covered along the horizontal direction in a time t is

d_x = v_x t

- The vertical motion of the skier is a uniformly accelerated motion, with initial velocity u_y = 0 and constant acceleration g=9.8 m/s^2 (where we take the downward direction as positive direction). Therefore, the vertical distance covered in a time t is

d_y = \frac{1}{2}gt^2

The time t at which the skier lands is the time at which the skier reaches the incline, whose slope is

\theta = 36^{\circ} below the horizontal

This happens when:

tan \theta = \frac{d_y}{d_x}

Substituting and solving for t, we find:

tan \theta = \frac{\frac{1}{2}gt^2}{v_x t}= \frac{gt}{2v_x}\\t = \frac{2v_x}{g}tan \theta = \frac{2(28)}{9.8} tan 36^{\circ} =4.15 s

b) 143.6 m

Here we want to find the distance covered along the slope of the incline, so we need to find the horizontal and vertical components of the displacement first:

d_x = v_x t = (28)(4.15)=116.2 m

d_y = \frac{1}{2}gt^2 = \frac{1}{2}(9.8)(4.15)^2=84.4 m

The distance covered along the slope is just the magnitude of the resultant displacement, so we can use Pythagorean's theorem:

d=\sqrt{d_x^2+d_y^2}=\sqrt{(116.2)^+(84.4)^2}=143.6 m

7 0
3 years ago
At the end of the adiabatic expansion, the gas fills a new volume V₁, where V₁ > V₀. Find W, the work done by the gas on the
tino4ka555 [31]

Answer:

W=\frac{p_0V_0-p_1V_1}{\gamma-1}

Explanation:

An adiabatic process refers to one where there is no exchange of heat.

The equation of state of an adiabatic process is given by,

pV^{\gamma}=k

where,

p = pressure

V = volume

\gamma=\frac{C_p}{C_V}

k = constant

Therefore, work done by the gas during expansion is,

W=\int\limits^{V_1}_{V_0} {p} \, dV

=k\int\limits^{V_1}_{V_0} {V^{-\gamma}} \, dV

=\frac{k}{\gamma -1} (V_0^{1-\gamma}-V_1^{1-\gamma})\\

(using pV^{\gamma}=k )

=\frac{p_0V_0-p_1V_1}{\gamma-1}

4 0
3 years ago
While performing an experiment involving a reaction between two chemicals, the scientist observes that the reaction container ha
AVprozaik [17]
When an object is becomes warm its an example of exothermic reaction.
8 0
3 years ago
A person walks 2.00 m east, then turns and goes 4.00 m west, then turns and goes back 1.00 m east.
bekas [8.4K]

Answer:

i got -1.00

Explanation:

7 0
3 years ago
Read 2 more answers
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