Answer:5
Explanation:
Given
First Plate has a charge of +Q and area A
Second Plate has a charge of -3 Q and area A
We Know electric Field due to sheet charge is given by
Where Q=charge over the Plate
A=Area of plate
= Permittivity of free space
Electric Field Due to Positive charge will always be away from it while for negative charge it is towards it.
Net Electric Field at a point between between the Plates is the superimposition of two electric with direction
Net electric Field is towards the negative charged plate
Answer:
I for a rod about its center is I = M L^2 / 12
A = L (1/2 - 1/3) = L / 6 distance from middle to location L/3
A^2 = L^2 / 36
I = M L^2 (1/12 + 1/36) = M L^2 (4 / 36) = M L^2 / 9
I about given location by parallel axis theorem
To do this you would take 64 and divide it by 4.
64/4= 16.
Your answer is 16.
Answer:
4.
Explanation:
Given,
frequency of standing wave = 603 Hz
length of string,L = 1.33 m
speed of the wave, v = 402 m/s
number of antinodes = ?
Wavelength of the standing wave
Number of anti nodes in the standing wave
n =3.97= 4.
Number of antinodes is equal to 4.
