The greater the mass of an object, the greater its force due to gravity

Iodine molecules separates into atoms after absorbing light of 450 nm. If one

OlgaM077 [116]

Answer:E = hc/? = 4.41 x 10-19 J

Energy absorbed by each atom :

E (atom) = 2.205 x 10-19 J

Now Bond Energy of each molecule (B) = 3.98 x J

So, for each atom 1.99 x 10-19 J

So now

KE of each atom = E(atom) - B (atom)

= 2.15 x 10-19 J

5 0

3 years ago

A visual poster can be used to helping the child?

creativ13 [48]

The correct answer is D. learn to do a task independently.

6 0

3 years ago

You're driving down the highway late one night at 20 m/s when a deer steps onto the road 44 m in front of you. Your reaction tim

never [62]

Answer:

14.0 m

25.1 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Distance traveled in the reaction time

Distance = Speed × Time

$\text{Distance}=20\times 0.5=10\ m$

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-20^2}{2\times -10}\\\Rightarrow s=20\ m$

Distance in which the car will stop is 10+20 = 30.0 m

So, the car will not hit the deer

Distance between the car and deer is 44-30 = 14.0 m

$\text{Distance}=u\times 0.5=0.5u\ m$

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u^2=v^2-2as\\\Rightarrow u^2=0^2-2\times -10\times (44-0.5u)\\\Rightarrow u^2=20(44-0.5u)\\\Rightarrow u^2=880-10u\\\Rightarrow u^2+10u-880=0$

$u=\frac{-10+\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}, u=\frac{-10-\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}\\\Rightarrow u=25.08, -35.08\ m/s$

Maximum speed of the car by which it will not hit the deer is 25.1 m/s

5 0

3 years ago

Read 2 more answers

A man claims that he can hold onto a 15.0-kg child in a head-on collision as long as he has his seat belt on. Consider this man

suter [353]

Answer:

F= 5195.625 N

Explanation:

To obtain the force needed to hold the child, we need to know the aceleration in which the car is breaking.

Aceleration is equal to velocity divided by the time of breaking

In international system, velocity [m/s] is

v= (62 mi/h)*(1609 m/mi)*(1 h/3600 s)

v= 27.71 m/s

Now, we part the velocity by the time that is 0.08 seconds

a= v/t= (27.71 m/s)/(0.08 s)

a= 346.375 m/ $s^{2}$

The force in agreement with the Newton's second law is

F=m*a = 15 Kg*346.375 m/ $s^{2}$

F= 5195.625 N

(Note: 1 N = 1 Kg*m/ $s^{2}$ )

3 0

2 years ago

If a bar magnet is suspended at the center on a string and allowed to swing freely, in what direction will its south pole point

nika2105 [10]

Explanation : If a bar magnet is suspended at the center on a string and allow to swing freely, then the magnet will rotate so that it will line with the pole of the earth .

So, we can say that when the magnet suspended freely by the string, then the magnet will rotate and stop in north and south direction . The north pole of the magnet will stop in the south direction of the earth and the south pole of the magnet will stop in the north direction of the earth.

8 0

2 years ago