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tatuchka [14]
3 years ago
7

The greater the mass of an object, the greater its force due to gravity

Physics
1 answer:
Serga [27]3 years ago
6 0
What is the question?
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Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal po
zvonat [6]

Answer:

0.293I_0

Explanation:

When the unpolarized light passes through the first polarizer, only the component of the light parallel to the axis of the polarizer passes through.

Therefore, after the first polarizer, the intensity of light passing through it is halved, so the intensity after the first polarizer is:

I_1=\frac{I_0}{2}

Then, the light passes through the second polarizer. In this case, the intensity of the light passing through the 2nd polarizer is given by Malus' law:

I_2=I_1 cos^2 \theta

where

\theta is the angle between the axes of the two polarizer

Here we have

\theta=40^{\circ}

So the intensity after the 2nd polarizer is

I_2=I_1 (cos 40^{\circ})^2=0.587I_1

And substituting the expression for I1, we find:

I_2=0.587 (\frac{I_0}{2})=0.293I_0

5 0
2 years ago
If a sheep is running at 3.0 m/s with a mass of 60 kg what is its kinetic energy​
borishaifa [10]

Answer:270joules

Explanation:KE = 1/2mv^2

KE = 1/2(60kg)(3.0)^2 = 270 Joules

8 0
3 years ago
The moons of Mars, Phobos (Fear) and Deimos (Terror), are very close to the planet compared to
katrin2010 [14]

Answer:D- 0.2528

Explanation:

T=(Rp/Rd)^3/2

T=(9378/23459)^3/2

T=0.2528

The answer is D

3 0
3 years ago
What is the magnitude of the momentum change of two gallons of water (inertia about 7.3 kg ) as it comes to a stop in a bathtub
aliya0001 [1]

We know that the change in momentum is equals to the product of force and time that is impulse (  F \times t). Therefore, we need to determine the value of that the water is in air by using the second equation of motion,

s=ut+\frac{1}{2} gt^2

Here, u is initial velocity which is zero.

s= \frac{1}{2} gt^2 \\\\ t = \sqrt{\frac{2s}{g} }.

Thus, impulse

= F \times \sqrt{\frac{2s}{g} }

From Newton`s second law,

F =mg

Therefore, impulse

= mg \times \sqrt{\frac{2s}{g} } = m \sqrt{2gs}

Given,  m = 7.3 kg and s = 2.0 m

Substituting these values, we get

Change in momentum = impulse  

= 7.3 \ kg \sqrt{2 \times 9.8 \ m/s^2 \times 2.0 \ m } = 45 .7 \ Ns.

8 0
2 years ago
Sound travels faster in: steel water sir
alukav5142 [94]
Sound travels better in water
8 0
3 years ago
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