Answer:
1. Dheere Dheere (slowly slowly)
2. Har (every)
3. Kal (tomorrow)
4. Mat (don't)
5. Andar (inside)
sorry I wasn't able to write in hindi
Lets assume that s is the speed of the slower train and f is the speed of the faster train.
s = f - 16
f = 150 / t
s = 170 / ( t+2 )
-----------------------
170 / ( t+2 ) = 150 / t - 16 / t * ( t + 2 )
170 t = 150 * ( t + 2 ) - 16 t * ( t + 2 )
170 t = 150 t + 300 - 16 t² - 32 t
16 f² + 52 t - 300 = 0 / : 4 ( We will divide both sides of the equation by 4 )
4 t² + 13 t - 75 = 0
t 1/2 = ( -13 + √(169 + 1200 ) )/ 8
t = ( - 13 + 37 ) / 8 = 24 / 8 = 3
t = 3 h
s = 170 : ( 3 + 2 ) = 170 : 5 = 34 mph
Answer: The speed of the slower train is 34 mph.
Answer:
Explanation:
Given
Required
Determine the percentage error
First, we calculate the mean
This gives:
Next, calculate the mean absolute error (E)
This gives:
![|E| = \sqrt{\frac{1}{6}*[(1.54 - 1.51)^2 +(1.53- 1.51)^2 +.... +(1.45- 1.51)^2]}](https://tex.z-dn.net/?f=%7CE%7C%20%3D%20%5Csqrt%7B%5Cfrac%7B1%7D%7B6%7D%2A%5B%281.54%20-%201.51%29%5E2%20%2B%281.53-%201.51%29%5E2%20%2B....%20%2B%281.45-%201.51%29%5E2%5D%7D)
Next, calculate the relative error (R)
Lastly, the percentage error is calculated as:
Answer is option C. nitrogen as:-
OXYGEN- 21%
NITROGEN- 78%
CARBON DIOXIDE, ARGON, NEON and SEVERAL OTHER GASES- 1%
