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tatuchka [14]
3 years ago
7

The greater the mass of an object, the greater its force due to gravity

Physics
1 answer:
Serga [27]3 years ago
6 0
What is the question?
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A man pushes on piano with mass 170 kg; it slides at constant velocity down a ramp that is inclined at 20.0 ∘ above the horizont
nikdorinn [45]

Answer

given,                            

mass of the piano = 170 kg              

angle of the inclination = 20°                

moves with constant velocity hence acceleration = 0 m/s²    

neglecting friction                                  

so, force required to pull the piano                    

F = m g sin θ                                                      

F = 170 × 9.81 × sin 20°                                        

F = 570.39 N                                                    

so, force required by the man to push the piano is F = 570.39 N

4 0
3 years ago
Which statement about projectile motion is true?
Svetllana [295]

C. The range of a projectile increases with an increase in the angle of launch.

3 0
3 years ago
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when the particles of the medium move back and forth along the direction of the wave motion, the wave is a
Bezzdna [24]

Transverse waves are always characterized by particle motion being perpendicular to wave motion. A longitudinal wave is a wave in which particles of the medium move in a direction parallel to the direction that the wave moves.

8 0
3 years ago
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A patient has an ongoing history of cancer. She has a tumor in the abdominal region, and has been undergoing treatment for it. T
Vadim26 [7]

Answer:

the answer is at the BOTTOM OF THEIR QUESTION

Explanation:

IT IS CORRECT BTW

6 0
3 years ago
An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.80 kW. A receiving antenna 7
Alecsey [184]

Answer:0.1759 v

Explanation:

Intensity of wave at receiver end is

I=\frac{P_{avg}}{A}

I=\frac{3.80\times 10^3}{4\times \pi \times \left ( 4\times 1609.34\right )^2}

I=7.296\times 10^{-6} W/m^2

Amplitude of electric field at receiver end

E_{max}=\sqrt{2I\mu _0c}

Amplitude of induced emf

=E_{max}d

=\sqrt{2\times 7.29\times 10-6\times 4\pi \times 3\times 10^8}\times 0.75

=17.591\times 10^{-2}=0.1759 v

7 0
3 years ago
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