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statuscvo [17]
3 years ago
5

A student has designed a circuit with one battery, two light bulbs, and two switches, pictured to the left. She would like for e

ach switch to control one light bulb, so that when one switch is open and the other is closed, one of the light bulbs will remain lit. From the image, we can see that neither light bulb is lit, even though one of the switches is closed. What is the error the student made? Your explanation should include a discussion of the flow of electrons in the circuit.

Physics
2 answers:
Gnoma [55]3 years ago
5 0

Answer:

The bulb is not powered because the negative end of the battery is not connected to the electric current,making it dysfunctional. The electrons have to flow through the positive and negative ends of the battery in order for it to work.

Hope this helps.

Misha Larkins [42]3 years ago
5 0
A.Switch the circuits A hopes this helps you out
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How much work (in J) is required to expand the volume of a pump from 0.0 L to 2.7 L against an external pressure of 1.0 atm?
spin [16.1K]

Answer:

-2.79 x 10²J

Explanation:

using the pressure volume work formula which states that

work = -PΔV

           = -(1.0 atm) (2.7-0.0)L = -2.7L . atm

Convert litre.atmosphere to Joules.

1 L . atm = 101.325 joules

-2.75 L .atm = -2.75 x 101.325 = -278.64375 =

Work = -2.79 x 10²J

5 0
4 years ago
A stone of mass m is thrown upwards at an angle φ. The moment the stone leaves your hand it has an acceleration (friction is neg
Lelechka [254]
The correct answer is:

= g

Explanation:

When the object leaves the hand it has a force acted on it mainly it’s weight.
5 0
3 years ago
A body in uniform velocity has zero acceleration why?
NikAS [45]
When the velocity is uniform, the velocity does not change. since acceleration is the rate of change in velocity, the acceleration will be zero when velocity is uniform
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4 years ago
Read 2 more answers
Introduction Team Problem 2 You jump into the deep end of Legion Pool and swim to the bottom with a pressure gauge. The gauge at
Kaylis [27]

Answer:

Depth of the pool, h = 4.004 cm

Explanation:

Pressure at the bottom, P = 39240 N/m²

The density of water, d = 1000 kg/m³

The pressure at the bottom is given by :

P = dgh

We need to find the depth of pool. Let h is the depth of the pool. So,

h=\dfrac{P}{dg}

h=\dfrac{39240\ N/m^2}{1000\ kg/m^3\times 9.8\ m/s^2}

h = 4.004 m

So, the pool is 4.004 meters pool. Hence, this is the required solution.

5 0
4 years ago
Need help with this question. Thirty points.
Anon25 [30]

1)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2 \\\\\implies m = \dfrac{2E_k}{v^2} = \dfrac{2\times 4500}{30^2}=10~ kg\\ \\2)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12mv^2 \\\\\implies v^2 = \dfrac{2E_k}m\\\\\implies v  = \sqrt{\dfrac{2E_k}{m}}=\sqrt{\dfrac{2 \times 320}{\dfrac{20}{9.8}}}= 17.709 ~ ms^{-1}\\\\3)\\\\\text{Kinetic energy,}\\\\E_k=\dfrac 12 mv^2=\dfrac 12 \times 50 \times 10^2=2500 ~J\\\\\\

4)\\\\\text{Potential energy,}\\\\E_p =mgh = 5\times 9.8\times 1.5 = 73.5 ~J

5 0
2 years ago
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