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ZanzabumX [31]
3 years ago
14

Use the Pythagorean theorem to answer the following question. A ping-pong ball is shot straight north from a popgun at 4.0 m/s.

The wind is blowing to the west at 3.0 m/s. What is the actual velocity of the ping-pong ball?

Physics
2 answers:
dybincka [34]3 years ago
5 0

Answer : The actual velocity of the ping-pong ball is, 5 m/s

Explanation :

Using Pythagorean theorem :

(Hypotenuse)^2=(Base)^2+(Perpendicular)^2

The diagram is shown below.

From the diagram we conclude that,

AB = 4 m/s

BC = 3 m/s

AC = ?

(AC)^2=(BC)^2+(AB)^2

Now put all the given values in this formula, we get

(AC)^2=(3)^2+(4)^2

AC=5m/s

Therefore, the actual velocity of the ping-pong ball is, 5 m/s

MaRussiya [10]3 years ago
4 0
Resultant is 5 m/s using the Pythagorean theorem<span />
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Explanation:

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             t_ =  0.99998666657   s

             

therefore the time change is

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this is the delay in each second, therefore we can use a direct rule of proportions. If Δt was delayed every second, how much second (#_time) is needed for a total delay of Δt = 1 s

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At the instant the two balls collide, they will have the same displacement, therefore

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