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ZanzabumX [31]
3 years ago
14

Use the Pythagorean theorem to answer the following question. A ping-pong ball is shot straight north from a popgun at 4.0 m/s.

The wind is blowing to the west at 3.0 m/s. What is the actual velocity of the ping-pong ball?

Physics
2 answers:
dybincka [34]3 years ago
5 0

Answer : The actual velocity of the ping-pong ball is, 5 m/s

Explanation :

Using Pythagorean theorem :

(Hypotenuse)^2=(Base)^2+(Perpendicular)^2

The diagram is shown below.

From the diagram we conclude that,

AB = 4 m/s

BC = 3 m/s

AC = ?

(AC)^2=(BC)^2+(AB)^2

Now put all the given values in this formula, we get

(AC)^2=(3)^2+(4)^2

AC=5m/s

Therefore, the actual velocity of the ping-pong ball is, 5 m/s

MaRussiya [10]3 years ago
4 0
Resultant is 5 m/s using the Pythagorean theorem<span />
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<h3>What is cellular respiration?</h3>

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The food is prepared by the plants by the process of photosynthesis in presence of sunlight. This food is in the form of glucose.

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3 years ago
Which describes the average velocity of an ant traveling at a constant speed
yanalaym [24]

Answer: A. The total displacement divided by the time and  C. The slope of the ant's displacement vs. time graph.

Explanation:

Hi! The question seems incomplete, but I found the options on the internt:

A. The total displacement divided by the time.

B. The slope of the ant's acceleration vs. time graph.

C. The slope of the ant's displacement vs. time graph.

D. The average acceleration divided by the time.

Now, since we know the ant is travelling at a constant speed, its average velocity V will be expressed by the following equation:

V=\frac{d}{t}

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d is the ant's total displacement

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Hence one of the correct options is: A. The total displacement divided by the time

On the other hand, this can be expressed by a displacement vs. time graph graph, where the slope of that line leads to the equation written above. So, the other correct option is: C. The slope of the ant's displacement vs. time graph.

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Two identical satellites orbit the earth in stable orbits. Onesatellite orbits with a speed vat a distance rfrom the center of t
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Answer:

c) At a distance greater than r

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If G= Gravitational constant

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then orbital speed is ;

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If speed of first satellite = V₁

==> V₁² = GM/r

==> r = GM/V₁²

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Information about the problem:

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Applying the distance formula we have that:

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<h3>What is velocity?</h3>

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