Answer:
The work and heat transfer for this process is = 270.588 kJ
Explanation:
Take properties of air from an ideal gas table. R = 0.287 kJ/kg-k
The Pressure-Volume relation is <em>PV</em> = <em>C</em>
<em>T = C </em> for isothermal process
Calculating for the work done in isothermal process
<em>W</em> = <em>P</em>₁<em>V</em>₁ ![ln[\frac{P_{1} }{P_{2} }]](https://tex.z-dn.net/?f=ln%5B%5Cfrac%7BP_%7B1%7D%20%7D%7BP_%7B2%7D%20%7D%5D)
= <em>mRT</em>₁ [∵<em>pV</em> = <em>mRT</em>]
= (5) (0.287) (272.039) ![ln[\frac{2.0}{1.0}]](https://tex.z-dn.net/?f=ln%5B%5Cfrac%7B2.0%7D%7B1.0%7D%5D)
= 270.588 kJ
Since the process is isothermal, Internal energy change is zero
Δ<em>U</em> = 
From 1st law of thermodynamics
Q = Δ<em>U </em>+ <em>W</em>
= 0 + 270.588
= 270.588 kJ
Answer:120 min
Explanation:
Given
Amanda spent 
of her time after school doing Home work
And 
of her remaining time riding her bike
It is given that she rode her bike for 45 minutes in a week
Let t be the time after school
therefore Amanda spend 
in home work and 
time is left
From remaining time she spends time riding her bike
therefore 
thus 
therefore time spent on home work is 
To solve this problem we will use the definition of the kinematic equations of centrifugal motion, using the constants of the gravitational acceleration of the moon and the radius of this star.
Centrifugal acceleration is determined by
Where,
v = Velocity
r = Radius
From the given data of the moon we know that gravity there is equivalent to
While the radius of the moon is given by
If we rearrange the function to find the speed we will have to
The speed for this to happen is 1.7km/s
The mean of the velocities.
(finalVelocity + initialVelocity)/2
