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7nadin3 [17]
3 years ago
14

A light with a second-order bright band forms a diffraction angle of 30.0°. The diffraction grating has 250.0 lines per mm. What

is the wavelength of the light? 800 nm 1,000 nm 1,386 nm 1,732 nm
Physics
2 answers:
Simora [160]3 years ago
7 0
I have no idea sorry
Effectus [21]3 years ago
5 0

Answer:

B.1000 nm

Explanation:

I just took the test

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12. Energy from the breaking of atomic bonds in molecules (ex: C4 explosion)
Korolek [52]

Answer:

endothermic energy or chemical energy

Explanation:

An endothermic process increases the enthalpy H of the system, during which the closed system (usually) absorbs thermal energy from its surroundings.

Chemical energy is the form of potential energy in which energy is stored in chemical bonds. The breaking of chemical bonds absorbs energy, while the formation of new bonds releases energy.

6 0
3 years ago
When a metal bonds with a nonmetal, they form a(n)
MArishka [77]
I believe it would be B.
5 0
4 years ago
CORRECT ANSWER WILL BE REWARDED BRAINLIEST
Mandarinka [93]

Answer:

What is 2^-3 x 3^-2 as a fraction?

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Explanation:

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3 years ago
Balanced or un balanced
sattari [20]

Answer: unbalance

Explanation:

5 0
3 years ago
at a particular instant a hot air balloon is 100m in the air and decending at a constant speed of 2m/s at this exact instant a g
labwork [276]
<h2>She will find the ball at a horizontal distance of 86.4 m from landed location</h2>

Explanation:

Consider the vertical motion of ball

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 2 m/s

        Acceleration, a = 9.81 m/s²  

        Displacement, s = 100 m      

     Substituting

                      s = ut + 0.5 at²

                      100 = 2 x t + 0.5 x 9.81 xt²

                      4.905t²  + 2t - 100 = 0

                     t = 4.32 s    or   t = -4.72 s

                    After 4.32 seconds the ball reaches ground.

Now we need to find horizontal distance traveled by ball in 4.32 seconds.

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 20 m/s

        Acceleration, a = 0 m/s²  

        Time, t = 4.32 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 20 x 4.32 + 0.5 x 0 x 4.32²

                      s = 86.4 m

She will find the ball at a horizontal distance of 86.4 m from landed location

5 0
4 years ago
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