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7nadin3 [17]
3 years ago
14

A light with a second-order bright band forms a diffraction angle of 30.0°. The diffraction grating has 250.0 lines per mm. What

is the wavelength of the light? 800 nm 1,000 nm 1,386 nm 1,732 nm
Physics
2 answers:
Simora [160]3 years ago
7 0
I have no idea sorry
Effectus [21]3 years ago
5 0

Answer:

B.1000 nm

Explanation:

I just took the test

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Read 2 more answers
5) Find the initial velocity for a 700 kg car that
Serhud [2]

Answer:

Δv = 12 m/s, but we are not given the direction, so there are really an infinite number of potential solutions.

Maximum initial speed is 40.6 m/s

Minimum initial speed is 16.6 m/s

Explanation:

Assume this is a NET impulse so we can ignore friction.

An impulse results in a change of momentum

The impulse applied was

p = Ft = 1400(6.0) = 8400 N•s

p = mΔv

Δv = 8400 / 700 = 12 m/s

If the impulse was applied in the direction the car was already moving, the initial velocity was

vi = 28.6 - 12 = 16.6 m/s

if the impulse was applied in the direction opposite of the original velocity, the initial velocity was

vi = 28.6 + 12 = 40.6 m/s

Other angles of Net force would result in various initial velocities.

5 0
3 years ago
A conductor differs from an insulator in that a conductor.
Zina [86]

Answer:

has free electrons

Explanation:

A conductor has free electrons while an insulator does not. Free electrons are electrons which are not bounded tightly to their parent atoms, and are free to move given the right conditions (ie. a strong EM field).

4 0
2 years ago
A race car makes one lap around a track of radius 50 m in 9.0 s. What is the average velocity? *
Oksi-84 [34.3K]

Given that,

Radius of track, r = 50 m

time , t = 9 s

velocity, v = ?

Distance covered by car in one lap around a track is equal to the circumference of the track.

C = 2 π r = 2 * 3.14 * 50

C = 314.159 m

Distance covered by car, s = 314.159 m

Velocity = distance/ time

V = 314.159 / 9

V = 34.9 m/s

The average velocity of car is 34.9 m/s.

7 0
3 years ago
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