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valkas [14]
3 years ago
13

If the phase angle for a block–spring system in SHM is ϕ and the block's position is given by x = xm cos(ωt + ϕ), what is the ra

tio of the kinetic energy to the potential energy at time t = 0? (Use any variable or symbol stated above as necessary.)
Physics
1 answer:
matrenka [14]3 years ago
7 0

<h2>K.E/P.E = m/k  tan²φ x ω²</h2>

Explanation:

The given position of block x = x₀ cos(ωt + φ)

The velocity of block  v = dx/dt = - x₀ sin(ωt + φ) x ω

The kinetic energy = 1/2 mv² = 1/2 m x₀² sin²(ωt + φ) x ω²

The potential energy of spring = 1/2 k x² , where k is the spring constant

Thus P.E = 1/2 x k x x₀² cos²(ωt + φ)

When t = 0

K.E = 1/2 m x₀²sin²φ x ω²

P.E = 1/2 k x₀² cos²φ

Dividing these , we have

K.E/P.E = m/k  tan²φ x ω²

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What is the net force on an object that has a mass of 2.5 kg and accelerates to the right at 2 m/s?
Nadya [2.5K]

Answer:

5 N

Explanation:

The formula that you've to use to find the force is :

Force = Mass × Acceleration

They have already given that,

m = 2.5 kg

a = 2 ms⁻²

Let us find now.

F = m a

F = 2.5 kg ×  2 ms⁻²

F =  5 N

Hope this helps you :-)

Let me know if you have any other questions :-)

5 0
2 years ago
A spring has a period of 1 s when a 0.200 kg mass hung from the end of it. If the mass at the end is changed to 0.100 kg, will t
shutvik [7]

When the mass of the spring changed from 0.2kg to 0.1kg, the time period changed from 1 sec to 0.5 seconds

<u>Explanation:</u>

Given-

Mass, m1 = 0.2kg

Time period, T1 = 1s

m2 = 0.1 kg

T2 = ?

We know,

T = 2\pi \sqrt{\frac{m}{k} }

where,

T = Time period

m = mass

k = spring constant

From the equation, we can see that T is directly proportion to the square root of mass, m

T ∝ √m

So,

If m1 = 0.2kg , T1 = 1s and m2 = 0.1kg

The T2 would be:

\frac{T1}{T2} = \frac{m1}{m2} \\\\\frac{1}{T2} = \frac{0.2}{0.1} \\

T2 = \frac{1}{2} \\\\T2 = 0.5sec

Therefore, when the mass of the spring changed from 0.2kg to 0.1kg, the time period changed from 1 sec to 0.5 seconds

3 0
3 years ago
Two isolated copper plates, each of area 0.40 m2, carry opposite charges of magnitude 7.08 × 10-10 C. They are placed opposite e
polet [3.4K]

Answer:

The potential difference between the plates is 8 V.

Explanation:

Given that,

Area of plates = 0.40 m²

Charge q=7.08\times10^{-10}\ C

Distance = 4.0 cm

We need to calculate the electric field

Using for formula of electric field

E=\dfrac{2q}{2\epsilon_{0}A}

Where, q = charge

A = area

Put the value into the formula

E=\dfrac{7.08\times10^{-10}}{8.85\times10^{-12}\times0.40}

E=200\ V/m

We need to calculate the potential difference between the plates

Using formula of potential difference

V=E\times d

Where, E = electric field

d = distance

Put the value into the formula

V=200\times0.04

V=8\ V

Hence, The potential difference between the plates is 8 V.

3 0
4 years ago
The electrons in a particle beam each have a kinetic energy K. What is the magnitude of the electric field that will stop these
harina [27]

Answer:

Electric field magnitude

E = K/qd

Where

K = kinetic energy of electron

d = electron distance

q = charge

Explanation:

Given the relationship between workdone and energy

Work-energy theorem:

Net workdone = Energy change

W = ∆E

In this case

W = ∆K.E

And,

∆K.E = K(final) - K(initial)

To stop the kinetic energy | K(final) = 0

K(initial) = K (given)

∆K.E = 0 - K = -K

Let the electric force on the electron has magnitude F.

And

W = -Fd = ∆K.E = -K

-Fd = -K

F = K/d .....1

The magnitude of the electric field E that can stop these electron in a distance d:

E = F/q ......2

Where q is the charge on electron.

substituting equation 1 to 2

E = (K/d)/q = K/qd

E = K/qd

3 0
4 years ago
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Gelneren [198K]

In Burglar alarm, LDR acts an AND gate.

Answer: C

Explanation

The LDR is light dependent resistor. The principle used in the working of LDR is that the resistance is inversely proportional to the intensity of light falling on the diode.

In burglar alarm, LDR diode is combined with an IC 555.

Normally an LED source is made to be incident on the LDR diode with same intensity such that the resistance will be maintained constant.

As the LDR is connected with IC, the voltage will be high when light is falling on the diode.

The IC will give only two output states that is high and low. This confirms that LDR in burglar alarm act as AND gate.

As the thief enters and crosses the LED light, the intensity of the light falling on the diode will decrease leading to decrease in the voltage which will cause the alarm to beep.

4 0
3 years ago
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