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valkas [14]
3 years ago
13

If the phase angle for a block–spring system in SHM is ϕ and the block's position is given by x = xm cos(ωt + ϕ), what is the ra

tio of the kinetic energy to the potential energy at time t = 0? (Use any variable or symbol stated above as necessary.)
Physics
1 answer:
matrenka [14]3 years ago
7 0

<h2>K.E/P.E = m/k  tan²φ x ω²</h2>

Explanation:

The given position of block x = x₀ cos(ωt + φ)

The velocity of block  v = dx/dt = - x₀ sin(ωt + φ) x ω

The kinetic energy = 1/2 mv² = 1/2 m x₀² sin²(ωt + φ) x ω²

The potential energy of spring = 1/2 k x² , where k is the spring constant

Thus P.E = 1/2 x k x x₀² cos²(ωt + φ)

When t = 0

K.E = 1/2 m x₀²sin²φ x ω²

P.E = 1/2 k x₀² cos²φ

Dividing these , we have

K.E/P.E = m/k  tan²φ x ω²

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In this case, suppose that the premieres meet Rayleigh's criteria, which establishes that the central maximum of the diffraction of an object coincides with the first minimum of diffraction of the second object. In this case m = 1

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3 years ago
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VARVARA [1.3K]

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Explanation:

Explanation in pics:

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