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Ilya [14]
3 years ago
7

water flows horizontally from a hose that is 3m above the ground. the water lands 7.2m to the right of the hose . how long does

it take the water to reach the ground?
Physics
2 answers:
Sidana [21]3 years ago
8 0

Answer:

0.782 s

Explanation:

The water flows horizontally from the hose, so its initial vertical velocity is 0.

Given:

y₀ = 3 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t

y = y₀ + v₀ t + ½ at²

0 m = 3 m + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 0.782 s

Round as needed.

lora16 [44]3 years ago
3 0

Answer:

0.782 seconds

Explanation:

Water flows horizontally from a hose that is 3m above the ground. The water lands 7.2m to the right of the hose. Therefore, it will take 0.782 seconds for the water to reach the ground. We know this because, the water flows sideways in the hose, therefore, making its vertical velocity 0.

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Calculate the Latent Heat of Vaporization. (Please see picture attached)
Hunter-Best [27]

Answer:

20 J/g

Explanation:

In this question, we are required to determine the latent heat of vaporization

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What is latent heat of vaporization?

  • It is the amount of heat required to change a substance from its liquid state to gaseous state without change in temperature.
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How do we calculate the latent heat of vaporization?

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In this case;

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Thus,

Latent heat of vaporization = Quantity of Heat ÷ Mass

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aliya0001 [1]

Answer: The observing friend will the swimmer moving at a speed of 0.25 m/s.

Explanation:

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  • Note that this speed is the magnitude of the velocity which is a vector quantity.
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Hence the resultant velocity is given as, S_{R} = S — S 0S_{0}

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