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Ilya [14]
3 years ago
7

water flows horizontally from a hose that is 3m above the ground. the water lands 7.2m to the right of the hose . how long does

it take the water to reach the ground?
Physics
2 answers:
Sidana [21]3 years ago
8 0

Answer:

0.782 s

Explanation:

The water flows horizontally from the hose, so its initial vertical velocity is 0.

Given:

y₀ = 3 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t

y = y₀ + v₀ t + ½ at²

0 m = 3 m + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 0.782 s

Round as needed.

lora16 [44]3 years ago
3 0

Answer:

0.782 seconds

Explanation:

Water flows horizontally from a hose that is 3m above the ground. The water lands 7.2m to the right of the hose. Therefore, it will take 0.782 seconds for the water to reach the ground. We know this because, the water flows sideways in the hose, therefore, making its vertical velocity 0.

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Explanation:

5 0
4 years ago
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An aluminum wire having a cross-sectional area equal to 3.00 10-6 m2 carries a current of 7.00 A. The density of aluminum is 2.7
Natali [406]

Answer:

Vd = 2.42 ×10⁻⁴ m/s

Explanation:

Given: A = 3.00×10⁻⁶ m², I = 7.00 A, ρ = 2.70 g/cm³

To find Drift Velocity Vd=?

Sol

the formula is Vd = I/nqA             (n is the number of charge per unit volume)

n = No. of electron in a mole ( Avogadro's No.) / Volume

Volume = Molar mass / density   ( molar mass of Al =27 g)

V = 27 g / 2.70 g/cm³ = 10 cm³ = 1 × 10 ⁻⁵ m³

n= (6.02 × 10 ²³) / (1 × 10 ⁻⁵ m³)

n= 6.02 × 10 ²⁸

Now

Vd = (7A) / (  6.02 × 10 ²⁸ ×  1.6 × 10⁻¹⁹ C ×  3.00×10⁻⁶ m²)

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6 0
3 years ago
An alligator swims to the left with a constant velocity of 5 \,\dfrac{\text{m}}{\text s}5
dexar [7]

Answer:

The alligator will take t = 10 s to reach the final speed of 35 m/s

Explanation:

As we know that the initial speed of the alligator is 5 m/s

then it accelerate by given acceleration to reach the final speed of 35 m/s

so we will have

v_i = 5 m/s

v_f = 35 m/s

a = 3m/s^2

now we have

v_f = v_i + at

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t = 10 s

5 0
3 years ago
A cubical Gaussian surface surrounds two positive charges, each has a charge q 1 1 = + 3.90 × 10 − 12 3.90×10−12 C, and three ne
Masteriza [31]

Answer:

The electric flux is zero because charge is zero.

Explanation:

Given that,

Positive charge q_{1}=3.90\times10^{-12}\ C

Negative charge q_{2}=-2.60\times10^{-12}\ C

We need to calculate the total charged

Using formula of charge

Q_{enc}=2q_{1}+3q_{2}

Put the value into the formula

Q_{enc}=2\times3.90\times10^{-12}+3\times(-2.60\times10^{-12})

Q_{enc}=0

We need to calculate the electric flux

Using formula of electric flux

\phi=\dfrac{Q_{enc}}{\epsilon_{0}}

Put the value into the formula

\phi=\dfrac{0}{8.85\times10^{-12}}

Hence, The electric flux is zero because charge is zero.

7 0
3 years ago
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