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Ilya [14]
3 years ago
7

water flows horizontally from a hose that is 3m above the ground. the water lands 7.2m to the right of the hose . how long does

it take the water to reach the ground?
Physics
2 answers:
Sidana [21]3 years ago
8 0

Answer:

0.782 s

Explanation:

The water flows horizontally from the hose, so its initial vertical velocity is 0.

Given:

y₀ = 3 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t

y = y₀ + v₀ t + ½ at²

0 m = 3 m + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 0.782 s

Round as needed.

lora16 [44]3 years ago
3 0

Answer:

0.782 seconds

Explanation:

Water flows horizontally from a hose that is 3m above the ground. The water lands 7.2m to the right of the hose. Therefore, it will take 0.782 seconds for the water to reach the ground. We know this because, the water flows sideways in the hose, therefore, making its vertical velocity 0.

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If a force always acts perpendicular to an object's direction of motion, that force cannot change the object's kinetic energy.
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2 years ago
What must be the pressure difference between the two ends of a 2.6 km section of pipe, 36 cm in diameter, if it is to transport
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Explanation:

This problem can be solved by the following equation:

\Delta P=\frac{8 \eta L Q}{\pi r^{4}}

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L=2.6 km=2600 m is the length of the pipe

Q=900 \frac{cm^{3}}{s} \frac{1 m^{3}}{(100 cm)^{3}}=0.0009 \frac{m^{3}}{s} is the Rate of flow of the fluid

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r=\frac{d}{2}=0.18 m is the radius of the pipe

Soving for \Delta P:

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