Answer:
V= 0.031L
Explanation:
P= 0.97atm, V= ?, n= 0.12/98 =0.00122mol, R= 0.082, T= 22.4+273= 295.4
Applying
PV=nRT
0.970×V = 0.00122×0.082×295.4
Simplify the above equation
V= 0.031L
Answer:
1) Increase temperature
2) Decrease temperature
3) Increase concentration of reactants
4) Increase pressure
5) Decrease pressure
Explanation:
Le Chatelier's Principle Fundamentals states that a chemical reaction at equilibrium that undergoes changes to pressure, temperature, or concentration, this will cause the equilibrium to shift in the opposite direction to offset the change.
1) Increase temperature
2) Decrease temperature
3) Increase concentration of reactants
4) Increase pressure
5) Decrease pressure
Answer:
151200 minutes.
Explanation:
From the question given above, the following data were obtained:
Time (in week) = 15 weeks
Time (in min) =?
Next, we shall convert 15 weeks to days. This can be obtained as follow:
1 week = 7 days
Therefore,
15 weeks = 15 weeks × 7 days / 1 week
15 weeks = 105 days
Next, we shall convert 105 days to hours. This can be obtained as follow:
1 day = 24 h
Therefore,
105 days = 105 days × 24 h / 1 day
105 days = 2520 h
Finally, we shall convert 2520 h to mins. This can be obtained as follow:
1 h = 60 mins
Therefore,
2520 h = 2520 h × 60 mins / 1 h
2520 h = 151200 mins
Thus, 15 weeks is equivalent to 151200 minutes.
Answer:
The correct option is;
4 percent ionic, 96 percent covalent, 222 pm
Explanation:
The parameters given are;
Phosphorus:
Atomic radius = 109 pm
Covalent radius = 106 pm
Ionic radius = 212 pm
Electronegativity of phosphorus = 2.19
Selenium:
Atomic radius = 122 pm
Covalent radius = 116 pm
Ionic radius = 198 pm
Electronegativity of selenium= 2.55
The percentage ionic character of the chemical bond between phosphorus and selenium is given by the relation;
Using Pauling's alternative electronegativity difference method, we have;
![\% \, Ionic \ Character = \left [18\times (\bigtriangleup E.N.)^{1.4} \right ] \%](https://tex.z-dn.net/?f=%5C%25%20%5C%2C%20Ionic%20%5C%20Character%20%3D%20%5Cleft%20%5B18%5Ctimes%20%28%5Cbigtriangleup%20E.N.%29%5E%7B1.4%7D%20%20%5Cright%20%5D%20%5C%25)
Where:
Δ E.N. = Change in electronegativity = 2.55 - 2.19 = 0.36
Therefore;
![\% \, Ionic \ Character = \left [18\times (0.36)^{1.4} \right ] \% = 4.3 \%](https://tex.z-dn.net/?f=%5C%25%20%5C%2C%20Ionic%20%5C%20Character%20%3D%20%5Cleft%20%5B18%5Ctimes%20%280.36%29%5E%7B1.4%7D%20%20%5Cright%20%5D%20%5C%25%20%3D%204.3%20%5C%25)
Hence the percentage ionic character = 4.3% ≈ 4%
the percentage covalent character = (100 - 4.3)% = 95.7% ≈ 96%
The bond length for the covalent bond is found adding the covalent radii of both atoms as follows;
The bond length for the covalent bond = 106 pm + 116 pm = 222 pm.
The correct option is therefore, 4 percent ionic, 96 percent covalent, 222 pm.
h2+o2=2h2o.................................................
