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3 years ago

U HUCUS 13 HUU

Chemistry

1 answer:

mario62 [17]3 years ago

4 0

Answer:

The correct answer is a the central core and is composed of protons and neutrons.

Explanation:

Nucleus is present in the center of an atom.Nucleus contain positively charged particle proton along with neutron which is neutral.

Due to the the presence of protons nucleus contain positive(+ve) charge.

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The table below provides some information about an unidentified element. Based on this information, the unidentified element is

Leona [35]

In the physical properties, it is mentioned that the element has 4 valence electrons. The elements in the periodic table are arranged such that, the number of valence electrons present in the neutral atoms belonging to a particular group is equal to the group number.

Thus, the unidentified element can be best classified as a nonmetal in period 4

Ans C)

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3 years ago

Which of the following solutions represents a good buffer system? a solution that is 0.10 mol L-1 NaOH and 0.10 mol L-1 KOH a so

Goshia [24]

Answer:

chu papi

Explanation:

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2 years ago

An arrow is moving at 35m/sand travels for 5 seconds.how far did the arrow travel?

docker41 [41]

Answer:

175 meters

Explanation:

As it's velocity is 35m/s

so,

by formula

35 *5

175 meters

8 0

3 years ago

Which is most often used to destroy bacteria?

vovangra [49]

Iodine- in most cleaning solutions

7 0

3 years ago

Calculate the number of pounds of CO2 released into the atmosphere when a 22.0 gallon tank of gasoline is burned in an automobil

IrinaK [193]

Answer:

391.28771 pounds of carbon-dioxide released into the atmosphere.

Explanation:

Density of the gasoline ,d= 0.692 g/mL

Volume of gasoline in an tanks,V = 22.0 gallons = 83,279.02 mL

Let mass of the gasolin be M

$d=\frac{M}{V}$

M = V × d = 83,279.02 mL × 0.692 g/mL=57,629.081 g

Assume that gasoline is primarily octane (given)

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

Mass of octane burnt in the tank = M = 57,629.081 g

Moles of octane = $\frac{57,629.081 g}{114.08 g/mol}=505.1637 mol$

According to reaction, 2 moles of octane gives 16 moles of carbon-dioxide.

Then 505.1637 mol of octane will give:

$\frac{16}{2}\times 505.1637 mol=4,041.3100 mol$ of carbon-dioxide

Mass of 4,041.3100 mol of carbon-dioxide:

4,041.3100 mol × 44.01 g/mol = 177,858.05 g

Mass of carbon-dioxide produced in pounds = 391.28771 pounds

391.28771 pounds of carbon-dioxide released into the atmosphe

4 0

3 years ago