Answer:
The answers are A,B,C.
Explanation: Just got it right on Edge 2020
Answer:
41264 g of CO₂
Explanation:
Combustion reaction is:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
1 mol of propane react to 5 moles of oxygen in order to proudce 3 moles of carbon dioxide and 4 moles of water.
In a combustion reaction, our reactant reacts to oxygen and the products are always CO₂ and water.
We have the volume of propane but we need moles of it, so we need to apply density.
Density = mass / volume so mass = density . volume.
Density of propane is: 493 g/L
Mass of propane is 493 g/L . 27.9L = 13754.7 g
We convert mass to moles: 13754.7 g . 1 mol/ 44g = 312.6 moles
According to reaction, 1 mol of propane can produce 3 moles of CO₂
Our 312.6 moles will produce 312.6 . 3 = 937.8 moles
We convert moles to mass: 937.8 mol . 44 g/mol = 41264 g
Where’s the image sorry this isn’t much help but I don’t know what to answer if I can’t see the image
Answer:
D would be the best answer
Explanation:
Answer:
1 Mole O₂ / 2 Mole H₂O
Explanation:
The balance chemical equation for the synthesis of water is as follow,
2 H₂ + O₂ → 2 H₂O
In this equation the moles are specified by the coefficients i.e.
2 moles of H₂ reacting with 1 mole of O₂
2 moles of H₂ producing 2 moles of H₂O
1 mole of O₂ producing 2 moles of H₂O
Hence the molar ratio for O₂ and H₂O can be written as,
1 Mole O₂ : 2 Mole H₂O
or,
1 Mole O₂ / 2 Mole H₂O
