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3 years ago

12

If you were standing at sea level measuring the air pressure, you would actually be measuring the air's _____. friction speed we

ight moisture

2 answers:

ira [324]3 years ago

6 0

Answer:

Weight

Explanation:

Pressure is the ratio of force and surface area. Thus, air pressure can be defined as the force exerted by the air over a surface area. This force exerted by the air is its weight.

Air pressure is the weight of the air column above a point. Air pressure depends on the density and length of the air column. At sea level, the density is high as compared to hills.

P = ρ g h

a_sh-v [17]3 years ago

4 0

The answer you're looking would be "weight." Hope this helps!

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A stream of warm air with a dry-bulb temperature of 36°C and a wet-bulb temperature of 30°C is mixed adiabatically with a stream

rewona [7]

Answer:

Explanation:

Given

$T_1\left ( DBT\right )=36^{\circ}C$

$WBT=30^{\circ}C$

$m_1=8 kg/s$

$m_2=10 kg/s$

Now total mass $m_3=sum of m_1+m_2$

$m_3=8+10=18 kg/sec$

Now from Steam table at DBT= $36^{\circ}C & WBT=30^{\circ}C$

$\omega _1=0.025$ kg\kg of dry air

for saturated cool air at $12^{\circ}C$

Humidity ratio $\omega _2=0.0085$ kg\kg of dry air

Now

$m_1\omega _1+m_2\omega _2=m_3\omega _3$

$8\cdot 0.025+10\cdot 0.0085=18\cdot \omega _3$

$\omega _3=0.01585$ kg/kg of dry air

Now

$m_1h_1+m_2h_2=m_3h_3$

$m_1C_pT_1+m_2C_pT_2=m_3C_pT_3$

$m_1T_1+m_2T_2=m_3T_3$

$8\cdot 36+10\cdot 12=18\cdot T_3$

$T_3=22.67^{\circ}C$

From Psychometric chart

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relative humidity ratio $\phi =0.89 or 89\%$

6 0

3 years ago

A light bulb radiates 110 nW of single-frequency sinusoidal electromagnetic waves uniformly in all directions. Calculate the ave

krek1111 [17]

Answer:

The intensity of the light from the bulb would be

3.501 x $10^{-6}$ W/ $m^{2}$

Explanation:

Given

The Power = 110 n W = 110 x $10^{-9}$ W

the distance r = 50 mm = 50 /1000 = 0.05 m

The intensity can be obtained with the relationship below;

I = Power/area ......1

The area of the sphere would be used in this case since the bulb is spherical; A=4π $r^{2}$

Putting it into equation 1, we have;

I = P/ 4π $r^{2}$

I = 110 x $10^{-9}$ / 4 x π x $0.05^{2}$

I = 3.501 x $10^{-6}$ W/ $m^{2}$

Therefore the intensity of the light from the bulb would be

3.501 x $10^{-6}$ W/ $m^{2}$

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Mars2501 [29]

Answer:

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