The dissociation constant of the base : 7.4 x 10⁻⁴
<h3>Further explanation</h3>
Butylamine, C4H9NH2 Is A Weak Base
Kb is the dissociation constant of the base.
LOH (aq) ---> L⁺ (aq) + OH⁻ (aq)
![\rm Kb=\dfrac{[L][OH^-]}{[LOH]}](https://tex.z-dn.net/?f=%5Crm%20Kb%3D%5Cdfrac%7B%5BL%5D%5BOH%5E-%5D%7D%7B%5BLOH%5D%7D)
[OH⁻] for weak base can be formulated :
![\tt [OH^-]=\sqrt{Kb.M}](https://tex.z-dn.net/?f=%5Ctt%20%5BOH%5E-%5D%3D%5Csqrt%7BKb.M%7D)
pH of solution : 12
pH+pOH=14, so pOH :
14-12 = 2, then :
![\tt [OH^-]=10^{-pOH}\\\\(OH^-]=10^{-2}](https://tex.z-dn.net/?f=%5Ctt%20%5BOH%5E-%5D%3D10%5E%7B-pOH%7D%5C%5C%5C%5C%28OH%5E-%5D%3D10%5E%7B-2%7D)
the the dissociation constant (Kb) =

Or you can use from ICE method :
C4H9NH2(aq) + H2O(l) ⇌ C4H9NH3+(aq) + OH-(aq)
0.15
x x x
0.15-x x x
![\tt Kb=\dfrac{x^2}{0.15-x}\rightarrow x=[OH^-]\\\\Kb=\dfrac{10^{-4}}{0.15-10^{-2}}=7.14\times 10^{-4}](https://tex.z-dn.net/?f=%5Ctt%20Kb%3D%5Cdfrac%7Bx%5E2%7D%7B0.15-x%7D%5Crightarrow%20x%3D%5BOH%5E-%5D%5C%5C%5C%5CKb%3D%5Cdfrac%7B10%5E%7B-4%7D%7D%7B0.15-10%5E%7B-2%7D%7D%3D7.14%5Ctimes%2010%5E%7B-4%7D)
Answer:
0.15 L
Explanation:
Step 1. Calculate the <em>moles of KF.</em>
Molar mass = 58.10 g/mol
Moles of KF = 8.0 × 1/58.10
Moles of KF = 0.138 mol KF
===============
Step 2. Calculate the <em>volume of KF
</em>
c = n/V Multiply both sides by V
V = 0.138 × 1/0.89
V = 0.15 L
Answer:sugar
Explanation:it is a homogeneous mixture
Ground is used for agriculture, sink water, hose water, and even drinking water (from the aqueducts).
Answer:
the atomic number is how you find the charge