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Art [367]
3 years ago
8

Nobody answering my questions what the answer givng brainliest

Chemistry
2 answers:
sergiy2304 [10]3 years ago
7 0

Answer: I think it’s B. Because as you can see from the picture there are layers

Explanation:

I think but just in case ask for a second opinion

just olya [345]3 years ago
7 0

Answer:

C. Air bubbles

Explanation:

Cant be A because.... you cant freeze a tempreature

Cant be B because... organism types cant show precipitation patterns.

Cant be D because....well it could be D, but there isnt a way to prove humans increased the tempreature

ITS C  hope it helps   :)

I also got this question before

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The molar mass of carbon dioxide (CO2) is 44.01 g/mol. The molar mass of water (H2O) is 18.01 g/mol. A reaction uses 528 g of CO
Black_prince [1.1K]
CO₂  +  H₂O  ------->  H₂CO₃

moles of CO₂ = \frac{MASS  of  Carbon}{ MOLAR  MASS}
              
                       = \frac{528  g}{44.01  g / mol}
 
                       =  11.997 mol

mole ratio of  CO₂  :  H₂O  =   1  :  1
           
            ∴ moles of H₂O  =  (`11.997 mol )  *  1
                                       =  11.997 mol
                                       ≈  12  mol
 
6 0
2 years ago
Write the net ionic equation for the reaction that takes places between aqueous copper and nitrate.
PIT_PIT [208]

Answer:

Cu+HNO3

Explanation:

7 0
3 years ago
Which is an example of a three
malfutka [58]

Answer:

It's A. 120 cubic meters

6 0
2 years ago
Read 2 more answers
A 2.20 mol sample of NO 2 ( g ) is added to a 3.50 L vessel and heated to 500 K. N 2 O 4 ( g ) − ⇀ ↽ − 2 NO 2 ( g ) K c = 0.513
igor_vitrenko [27]

Answer:

[NO₂] = 0.434 M

[N₂O₄] = 0.0971 M

Explanation:

The equilibrum is:  N₂O₄(g)  ⇆  2NO₂ (g)

1 moles of nitrogen (IV) oxide is in equilibrium with 2 moles of nitrogen dioxide.

Initally we only have 2.20 moles of NO₂. So let's write the equilibrium again:

              2NO₂ (g)   ⇆   N₂O₄(g)      

Initially   2.20 mol              -

React          x                      x/2

X amount has reacted, and the half has been formed, according to stoichiometry.

Eq       (2.20-x) / 3.50L     (x/2)/ 3.50L

We divide by the volume because we need molar concentrations. Let's make the Kc's expression:

Kc = [N₂O₄] / [NO₂]²

0.513 = ((x/2)/ 3.50L) /  [(2.20-x) / 3.50L]

0.513 = ((x/2)/ 3.50L) / [(2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / [2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / (4.84 - 4.40x + x²) / 12.25)

0.513 / 12.25 (4.84 - 4.40x + x²) = x/2 / 3.50

0.203 - 0.184x + 0.0419x² = x/2 / 3.50

3.50(0.203 - 0.184x + 0.0419x²) = x/2

7 (0.203 - 0.184x + 0.0419x²) - x = 0

1.421 - 2.288x + 0.2933x² = 0  → Quadratic formula

a = 0.2933 ;  b = -2.288 ; c = 1.421

(-b +- √(b²-4ac)) / (2a)

x₁ = 7.12

x₂ = 0.68 → We consider this value, so we can have a (+) concentration.

Concentrations in the equilibrium are:

[NO₂] = (2.20-0.68) / 3.50 = 0.434 M

[N₂O₄] = (0.68/2) / 3.50  = 0.0971 M

8 0
2 years ago
WHY is there a difference between how an electrolytes and non electrolytes affect collegiative properties?
natulia [17]
 <span>Colligative properties are dependent upon the number of molecules or ions present in solution. Therefore, 1 mole of Na2SO4 will produce 3 moles of ions and so it will have 3 times as much of an effect as 1 mole of sugar, which is not an electrolyte and can't dissociate to an appreciable extent.</span>
4 0
2 years ago
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