If the density of the universe is _____ than the critical density, than the universe will ____

The curve below shows the percentage of population of aquatic species that die in response to doses of pollutant A:

Elis [28]

Based on the trend produced by the dose - response graph, it would be best to evacuate the residents in other to prevent the increasing percentage of deaths due to the rising level of pollutant A.

The curve shows that the pollutant level in mg/kg of pollutant A is still increasing, hence, groundwater monitoring alone won't be the best decision to make.

Since the pollutant level is still increasing, then the spill level still need effective monitoring.

Evacuation of residents seems to be the best decision that should be taken based on the information interpreted on the graph.

Therefore, Evacuating residents to prevent rising death percentage is required as the pollutant level is yet to subside.

Learn more :brainly.com/question/24844489

8 0

3 years ago

The resistance, R, of a wire varies directly as its length and inversely as the square of its diameter. If the resistance of a w

lbvjy [14]

R is proportional to the length of the wire:

R ∝ length

R is also proportional to the inverse square of the diameter:

R ∝ 1/diameter²

The resistance of a wire 2700ft long with a diameter of 0.26in is 9850Ω. Now let's change the shape of the wire, adding and subtracting material as we go along, such that the wire is now 2800ft and has a diameter of 0.1in.

Calculate the scale factor due to the changed length:

k₁ = 2800/2700 = 1.037

Scale factor due to changed diameter:

k₂ = 1/(0.1/0.26)² = 6.76

Multiply the original resistance by these factors to get the new resistance:

R = R₀k₁k₂

R₀ = 9850Ω, k₁ = 1.037, k₂ = 6.76

R = 9850(1.037)(6.76)

R = 69049.682Ω

Round to the nearest hundredth:

R = 69049.68Ω

8 0

3 years ago

The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles tendon alt

drek231 [11]

Answer:

5 mm

Explanation:

Youngs's modulus (Y) is described by the following expression:

$Y=\frac{F*L}{\Delta L*A}$

Where F is the force exerted on the tendon, L is its length, A is its area and ΔL is its change in length (stretching).

The force in this case is 8 times the weight of the runner:

$F= 8*m*g\\F= 8*70*9.8\\F=5488 N$

Therefore, the change in length of the tendon is given by:

$\Delta L=\frac{F*L}{Y*A}\\\Delta L=\frac{5488*0.15}{0.15*10^{10}*1.1*10^{-4}}\\\Delta L= 0.004989 m$

the runner's Achilles tendon will stretch by 0.004989 m, which is roughly 5 mm.

8 0

3 years ago

Capacitors C1 = 5.85 µF and C2 = 2.80 µF are charged as a parallel combination across a 250 V battery. The capacitors are discon

posledela

Answer:

Q1_new = 515.68 µC

Q2_new = 246.82 µC

Explanation:

Since the capacitors are charged in parallel and not in series, then both are at 250 V when they are disconnected from the battery.

Then it is only necessary to calculate the charge on each capacitor:

Q1 = 5.85 µF * 250 V = 1462.5 µC

Q2 = 2.8 µF * 250 V = 700 µC

Now, we will look at 1462.5 µC as excess negative charges on one plate, and 1462.5 µC as excess positive charges on the other plate. Now, we will use this same logic for the smaller capacitor.

When there is a connection of positive plate of C1 to the negative plate of C2, and also a connection of the negative plate of C1 to the positive plate of C2, some of these excess opposite charges will combine and cancel each other. The result is that of a net charge:

1462.5 µC - 700 µC = 762.5 µC

Thus,762.5 µC of net charge will remain in the 'new' positive and negative plates of the resulting capacitor system.

This 762.5 µC will be divided proportionately between the two capacitors.

Q1_new = 762.5 µC * (5.85/(5.85 + 2.8)) = 515.68 µC

Q2_new = 762.5 µC * (2.8/(5.85 + 2.8) = 246.82 µC

4 0

4 years ago

ANSWER FAST PLEASE. The bottom of a box has a surface area of 25.0 cm 2 . The mass of the box is 34.0 kilograms. Acceleration du

Natasha_Volkova [10]

34 * 9.8 = 333.2
333.2 / 25 = 13.33

<u>B.13.3N/cm^2</u>

7 0

3 years ago

Read 2 more answers

If the density of the universe is _____ than the critical density, than the universe will _____.

If the density of the universe is _ than the critical density, than the universe will _.