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2 years ago

PLEASE HELP!! i’ll mark brainliest if you’re correct

Physics

2 answers:

Studentka2010 [4]2 years ago

6 0

All you would do is 10 - 5 and you would get 5

Leno4ka [110]2 years ago

5 0

5Newtons or 5N

Ten newtons minus five Newton’s is 5 Newton’s

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Which shows the correct order of events after the big bang occurred? strong force separated from the unified force, inflationary

LUCKY_DIMON [66]

Answer:

C) gravity separated from the unified force, strong force separated from the unified force, inflationary expansion occurred, electromagnetic and weak forces separated from the unified force, quarks and electrons formed

5 0

3 years ago

What is the frequency for a beam of electrons orbiting in a field of 4.62 x 10^-3 T? Let the mass of an electrons m = 9.31 x 10^

melisa1 [442]

Frequency: $1.27\cdot 10^8 Hz$

Explanation:

The force experienced by an electron in a magnetic field is

$F=qvB$

where

$q=1.6\cdot 10^{-19}C$ is the electron charge

v is the speed of the electron

B is the strength of the magnetic field

Since the force is perpendicular to the direction of motion of the electron, the force acts as centripetal force, so we can write:

$qvB=m\frac{v^2}{r}$

where

r is the radius of the orbit

$m=9.31\cdot 10^{-31}kg$ is the mass of the electron

Re-arranging the equation,

$\frac{v}{r}=\frac{qB}{m}$ (1)

We also know that in a circular motion, the speed is equal to the ratio between circumference of the orbit and orbital period (T):

$v=\frac{2\pi r}{T}$

Substituting into (1),

$\frac{2\pi}{T}=\frac{qB}{m}$

We also know that 1/T is equal to the frequency f, so

$f=\frac{qB}{2\pi m}$

In this problem,

$B=4.62\cdot 10^{-3}T$

Therefore, the frequency of the electrons is

$f=\frac{(1.6\cdot 10^{-19})(4.62\cdot 10^{-3})}{2\pi(9.31\cdot 10^{-31})}=1.27\cdot 10^8 Hz$

4 0

3 years ago

At an accident scene on a level road, investigators measure a car’s skid mark to be 88 m long. The accident occurred on a rainy

Oduvanchick [21]

Answer:

The the speed of the car is 26.91 m/s.

Explanation:

Given that,

distance d = 88 m

Kinetic friction = 0.42

We need to calculate the the speed of the car

Using the work-energy principle

work done = change in kinetic energy

$W=\Delta K.E$

$\mu\ mg\times d=\dfrac{1}{2}mv^2$

$v^2=2\mu g d$

Put the value into the formula

$v=\sqrt{2\times0.42\times9.8\times88}$

$v=26.91\ m/s$

Hence, The the speed of the car is 26.91 m/s.

3 0

3 years ago

Read 2 more answers

Explain why two different elements cannot occupy the same box in the periodic table

bezimeni [28]

They cant occupy the same box in the periodic table because each atom has a certain number of protons which is the atomic number and no two atoms have the same amount of protons.

8 0

3 years ago

Determine the energy stored in a parallel plate capacitor that is charged to a potential difference of 150 V. The plates are 4.5

Misha Larkins [42]

Answer: E = 1.93×10^-7 J

Explanation: The formulae for getting the energy stored in a capacitor is given as

E =Cv²/2

Where E = energy stored in capacitor (joules), C = capacitance of capacitor (farad), v = applied voltage =150v.

The formulae implies that we need to get the capacitance of the capacitor (C) first before we can get the energy.

From the parameters given to us

Area of plates =A = 87.5cm² = 87.5/10000 = 0.00875m²

Distance between plates = d = 4.50mm = 4.50/1000 = 0.0045m

C = ε0A/d

Where ε0 = permittivity of free space = 8.85×10^-12 F/m

C = 8.85×10^-12 × 0.00875/ 0.0045

C = 7.743×10^-14/0.0045

C = 1.72×10^-11 F.

Recall that E = Cv²/2

E = ( 1.72×10^-11 × 150×150) /2

E = 3.87×10^-7/2

E = 1.93×10^-7 J

7 0

3 years ago