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Ronch [10]
3 years ago
13

An objects weighs 30n on earth a second object weighs 30n on thee moon which has the greatest mass of is it the same

Physics
1 answer:
bulgar [2K]3 years ago
6 0
Mass is indirectly proportional to gravity, as moon has less gravity mass would be greater there, if weight of the object is same!

In short, your answer would be "Moon"

Hope this helps!
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If you we're in charge of designing a wire to cart electricity across your city, state or provide, which of the following proper
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In the picture at left. The launch height is 10m ball B mass 5kg has a launch velocity of 12 m/s and ball A mass 8 kg has a laun
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24

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3 years ago
An object is placed in front of a diverging lens, such that the object-to-image distance is 71 cm.
Pachacha [2.7K]

Explanation:

Given that,

Object-to-image distance d= 71 cm

Image distance = 26 cm

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u -v= d

u=71+26=97\ cm

We need to calculate the focal length

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

put the value into the formula

\dfrac{1}{f}=\dfrac{1}{-26}+\dfrac{1}{97}

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The focal length of the lens is 35.52.

(B). Given that,

Object distance = 95 cm

Focal length = 29 cm

We need to calculate the distance of the image

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

Put the value in to the formula

\dfrac{1}{-29}=\dfrac{1}{v}-\dfrac{1}{95}

\dfrac{1}{v}=\dfrac{1}{-29}-\dfrac{1}{95}

\dfrac{1}{v}=-\dfrac{124}{2755}

v=-22.21\ cm

We need to calculate the magnification

Using formula of magnification

m=\dfrac{v}{u}

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4 0
3 years ago
In a shuffleboard game, the puck slides a total of 12 m before coming to rest. If the coefficient ofkinetic friction between the
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Answer:

puck decelerates due to the kinetic frictional force μk mg

Explanation:

given data

total distance = 12 m

coefficient of kinetic friction = 0.28

solution

we will apply equation of motion that is

v² - u² = 2 × a × s    ................1

we know acceleration will be

a = \frac{-u^2}{2\times S}  

Then we have

Force = mass × acceleration   .................2

m × \frac{-u^2}{2\times S} = -μk mg

The puck decelerates due to the kinetic frictional force μk mg  

and frictional force is negative as it opposes the motion.

so we get initial velocity of the puck which is strike.

4 0
3 years ago
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