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Misha Larkins [42]
3 years ago
9

What is the common name of this?

Chemistry
1 answer:
drek231 [11]3 years ago
8 0

Answer:

butyl alcohol

Explanation:

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What is the pH of an acid with a [H+] of 1.0 x 10&amp;-4 M?<br><br> 1. 4<br> 2. 10<br> 3. 1<br> 4. 7
True [87]
PH scale is from 1 to 14 and indicates how acidic or basic a solution is. To find pH or pOH we need to know the H⁺ ion concentration or OH⁻ concentration.
pH can be calculated using the following equation;
pH = -log[H⁺]
the H⁺ concentration of the given acid is 1.0 x 10⁻⁴ M. substituting this we can find the pH 
pH = -log[1x10⁻⁴]
pH = 4
answer is 1) 4
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3 years ago
For the reaction co(g)+2h2(g)&lt;-&gt;ch3oh(g) at 700. k, equilibrium concentrations are [h2] = 0.072 m, [co] = 0.020 m, and [ch
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The balanced equation for the reaction is
CO(g) + 2H₂(g) ⇄ CH₃<span>OH(g)

Since given concentrations are at equilibrium state, the expression for the equilibrium constant, k can be written as
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By substitution,
   k = 0.030 M / 0.020 M x (<span>0.072 M</span>)²
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6 0
3 years ago
State the functional groups that undergo cracking and substitution reaction.
omeli [17]

Unsaturated organic compounds with a carbon-to-carbon double bond and alkynes with a carbon-to-carbon triple bond, as well as aldehydes and ketones with a carbon-to-oxygen double bond, undergo addition reactions.

8 0
2 years ago
Help pls before I end it all
qwelly [4]

Answer:

We might just have to end it together

Explanation:

I tried to answer it now I'm stuck in the same hole -_-

7 0
3 years ago
Read 2 more answers
What is the energy released in this β − β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e 19 40 K → 20 40 C a + − 1 0 e ? (The
Effectus [21]

<u>Answer:</u> The energy released in the given nuclear reaction is 1.3106 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{19}^{40}\textrm{K}\rightarrow _{20}^{40}\textrm{Ca}+_{-1}^{0}\textrm{e}

We are given:

Mass of _{19}^{40}\textrm{K} = 39.963998 u

Mass of _{20}^{40}\textrm{Ca} = 39.962591 u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(39.963998-39.962591)=0.001407u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.001407u)\times c^2

E=(0.001407u)\times (931.5MeV)    (Conversion factor:  1u=931.5MeV/c^2  )

E=1.3106MeV

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.

6 0
3 years ago
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