All categories

3 years ago

Why is it important to use the metric system when conducting scientific investigations?

Chemistry

1 answer:

mojhsa [17]3 years ago

4 0

Because its easier for scientists outside of the United States to understand your data.

You might be interested in

How does convection affect the earths atmosphere

mel-nik [20]

Answer:

I think the layers of the atmosphere does temperature increase with increasing height. It is affected by convection because it heats the lower atmosphere. It is affected by conduction because the is the transfer of thermal energy. I guess

Hope this help!

3 0

2 years ago

Convert 485 milligrams into grams

Zielflug [23.3K]

Answer:

look at the picture above

5 0

2 years ago

Read 2 more answers

the formula for sodium hydroxide is NaOH; the formula for potassium hydroxide is KOH. which two elements do you think are contai

Luden [163]

Answer:

oxygen and hydrogen :)

Explanation:

4 0

2 years ago

Calculate the lithium ion (Li+) concentration for a 0.821 M Li2S solution.

kondor19780726 [428]

The lithium ion[Li⁺]=1.642 M

<h3>Further explanation</h3>

Ionic compounds will dissociate into ions when dissolved in water. The strength of the dissociation depends on the strength of the electrolyte properties. The stronger it is, the more ions will dissociate

Reaction

Li₂S⇒2Li⁺+S²⁻

mol ratio Li₂S : Li⁺: S²⁻ = 1 : 2 : 1

so the lithium-ion (Li⁺) concentration :

$\tt 2\times 0.821=1.642~M$

6 0

2 years ago

Consider the following equation: SiO2 (s) + 3C (graphite) --> SiC (s) + 2CO (g) ΔH rxn = 624.6 kJ / mol rxn. Using the follow

DerKrebs [107]

<u>Answer:</u> The enthalpy of the formation of $SiC(s)$ is coming out to be -65.3 kJ/mol

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H^o$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]$

For the given chemical reaction:

$SiO_2(s)+3C\text{ (graphite)}(s)\rightarrow SiC(s)+2CO(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(SiC(s))})+(2\times \Delta H^o_f_{(CO(g))})]-[(1\times \Delta H^o_f_{(SiO_2(s))})+(3\times \Delta H^o_f_{(C(s))})]$

We are given:

$\Delta H^o_f_{(CO(g))}=-110.5kJ/mol\\\Delta H^o_f_{(SiO_2(s))}=-910.9kJ/mol\\\Delta H^o_f_{(C(s))}=0kJ/mol\\\Delta H^o_{rxn}=624.6kJ$

Putting values in above equation, we get:

$624.6=[(1\times \Delta H^o_f_{(SiC(s))})+(2\times (-110.5))]-[(1\times (-910.9))+(3\times (0))]\\\\\Delta H^o_f_{(SiC(s))}=-65.3kJ/mol$

Hence, the enthalpy of the formation of $SiC(s)$ is coming out to be -65.3 kJ/mol.

8 0

3 years ago