Answer:
<u>A. Magnet has a north pole and south pole.</u>
Explanation:
- A magnet has a north and south pole
- Magnets attract paper clips due to the metals present
- Magnetic fields are not visible
- North pole and south pole attract each other
Only the first statement is correct, the answer is (A).
Answer:
3rd option. 1–butanamine
Explanation:
To name the compound above, the following must be observed:
1. Locate the functional group in the chain. In this case the functional group is amine.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound. In this case, the longest chain has 4 carbon i.e butane.
3. Since the functional group is amine, the parent name becomes butanamine i.e replacing the –e at the end in butane with –amine
4. Indicate the position of the functional group in the chain. In this case the functional group is at carbon 1
5. Name the compound by putting the above together.
The name of the compound is:
1–butanamine or butan–1–amine
1.54 x 10⁶kW
Explanation:
The problem here is converting from megawatts into kilowatts.
Given 1540megawatts.
The mega- and kilo- watts are prefixes that denotes multiples of units.
1 megawatt = 10⁶watts
1 kilowatt = 10³watts
Now given 1540megawatts power to Kilowatt power;
We see that :
1000kW = 1mW
1540mW x
= 1.54 x 10⁶kW
learn more:
energy units brainly.com/question/4791744
#learnwithBrainly
Answer:
Electric engines have efficiencies of roughly 90% whilst combustion engines about 10% to 30%. This is because combustion engines emit much more heat, which is always energy that is not used as work, and thus increases inefficiency.
Explanation:
Answer:
16.02 g
Explanation:
the balanced equation for the decomposition of CuCO₃ is as follows
CuCO₃ --> CuO + CO₂
molar ratio of CuCO₃ to CO₂ is 1:1
number of CuCO₃ moles decomposed - 45 g / 123.5 g/mol = 0.364 mol
according to the molar ratio
1 mol of CuCO₃ decomposes to form 1 mol of CO₂
therefore 0.364 mol of CuCO₃ decomposes to form 0.364 mol of CO₂
number of CO₂ moles produced - 0.364 mol
therefore mass of CO₂ produced - 0.364 mol x 44 g/mol = 16.02 g
16.02 g of CO₂ produced