The question is not complete. Proposed completed question is:
When aqueous solutions of sodium chloride and silver nitrate are mixed, a double-displacement reaction occurs. What is the balanced equation for the reaction?
A.
NaCl(aq) + AgNO3(aq) --------NaNO3(aq) + AgCl(aq)
B.
NaCl(aq) + AgNO3(aq) -------- NaNO3(aq) + 3AgCl(s)
C.
NaCl(aq) + AgNO3(aq) --------- NaNO3(aq) + AgCl(s)
D.
NaCl(aq) + AgNO3(aq) --------- Na(s) + AgNO3Cl(aq)
E.
NaCl(aq) + AgNO3(aq) --------- NaNO3(aq) + ClAg(s)
Answer is
A.
NaCl(aq) + AgNO3(aq) --------NaNO3(aq) + AgCl(aq)
Explanation:
Following the law of conservation of energy, the total number of atoms in the reactant side is equal to the total number of atoms in the product side.
I think the answer should be 2.19 J/g*K. The specific heat means the energy absorbed by 1 g substance to increase 1 Kelvin temperature. And keep the unit the same.
Answer:
Less than
Explanation:
According to the question, the drop counter is counting four out of five drops of base added to the HCl. So when the titration will reach to the end point the volume of Base recorded will be less than the actual volume of the base dropped in the solution.
We will use law of equivalence for the calculation of concentration of HCl,
Where,
and
are molarity and volume of HCl and
and
are molarity of volume of the base added.
Thus concentration of HCl will be calculated as,

As the recorded
is less than the actual amount present in the solution, the calculated value of concentration of HCl will also be less than the actual.
The current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.
<h3>What is current?</h3>
The current is given as the product of the charge with time. In the electrochemical analysis of the nickel, there will be a reduction of the nickel ion to nickel. The formation is given as:

There is the deposition of 1 mole of Ni with 2 electrons transfer. The transfer of charge for 1 mole that is 58.7 grams Nickel is:

The mass of Ni to be deposited is 1.22 grams. The charge required is given as:

The current required to transfer 4010.7 C of charge in 1800 seconds is given as:

Thus, the current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.
Learn more about current, here:
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