Answer:
he average atomic mass of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance
The balanced equation for the above reaction is;
2K + Cl₂ ---> 2KCl
Stoichiomtery of K to KCl is 2:2
Potassium is the limiting reactant which is fully consumed in the reaction. The amount of product formed depends on amount of limits reactant present.
Number of moles of K reacted - 6.75 g/ 39 g/mol = 0.17 mol
Therefore number of KCl moles formed - 0.17 mol
Mass of KCl formed - 0.17 mol x 74.5 g/mol = 12.67 g
Heat moves easily through good conductors of heat (such as metals) and very slowly through heat insulators (such as wood or plastic).
:)
Answer:
0.396 M
Explanation:
Let's consider the following reaction.
2 COF₂(g) ⇌ CO₂(g) + CF₄(g)
We can find the concentrations at equilibrium using an ICE Chart.
2 COF₂(g) ⇌ CO₂(g) + CF₄(g)
I 2.00 0 0
C -2x +x +x
E 2.00-2x x x
The concentration equilibrium constant (Kc) is:
![Kc=4.10=\frac{[CO_{2}][CF_{4}]}{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } =(\frac{x}{2.00-2x} )^{2} \\\sqrt{4.10} = \frac{x}{2.00-2x}\\4.05-4.05x=x\\x=0.802](https://tex.z-dn.net/?f=Kc%3D4.10%3D%5Cfrac%7B%5BCO_%7B2%7D%5D%5BCF_%7B4%7D%5D%7D%7B%5BCOF_%7B2%7D%5D%5E%7B2%7D%20%7D%20%3D%5Cfrac%7Bx%5E%7B2%7D%20%7D%7B%282.00-2x%29%5E%7B2%7D%20%7D%20%3D%28%5Cfrac%7Bx%7D%7B2.00-2x%7D%20%29%5E%7B2%7D%20%5C%5C%5Csqrt%7B4.10%7D%20%3D%20%5Cfrac%7Bx%7D%7B2.00-2x%7D%5C%5C4.05-4.05x%3Dx%5C%5Cx%3D0.802)
The concentration of COF₂ at equilibrium is:
[COF₂] = 2.00-2x = 2.00-2(0.802) = 0.396 M