Answer:
0.897 J/g°C
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Mass (M) of substance = 155g
Initial temperature (T1) = 25.0°C
Final temperature (T2) = 40°C
Change is temperature (ΔT) = T2 – T1 = 40°C – 25.0°C = 15°C
Heat Absorbed (Q) = 2085 J
Specific heat capacity (C) of the substance =?
Step 2:
Determination of the specify heat capacity of the substance.
Applying the equation: Q = MCΔT, the specific heat capacity of the substance can be obtained as follow:
Q = MCΔT
C = Q/MΔT
C = 2085 / (155 x 15)
C = 0.897 J/g°C
Therefore, the specific heat capacity of the substance is 0.897 J/g°C
Answer:
Explanation:
Hello there!
In this case, according to the attached solubility chart, it is possible for us to realize that about 88 grams of KNO3 are soluble at 50 °C but just 30 grams are soluble at 20 °C in the same 100 g of water.
In such a way, the crystalized mass of this solute can be calculated by subtracting the mass at 50 °C and the mass at 20 °C:
Best regards!
Answer:
a process that involves rearrangement of the molecular or ionic structure of a substance, as opposed to a change in physical form or a nuclear reaction.
Explanation:
1. Increasing
2. Increasing
3. Decreasing
4. Increasing
5. Decreasing
