The total percent yield:
After the combustion reaction with methane, the percent yield was 66.7%.
Combustion of Methane:
- Methane produces a blue flame as it burns in the atmosphere.
- Methane burns in the presence of enough oxygen to produce carbon dioxide (CO₂) and water (H₂O).
- It creates a significant quantity of heat during combustion, making it an excellent fuel source.
The other reactant, air's excess oxygen, is always present, making methane the limiting reactant. As a result, the amount of CH₄ burned will determine how much CO₂ and H₂O are produced.
The following chemical process produces carbon dioxide from methane:
CH₄ + 2O₂ ⇒ CO₂ + 2H₂O
Calculations:
1. <u><em>Theoretical quantity of carbon dioxide:</em></u>
All calculations will be based on the amount of methane because the problem specifies that it is the limiting reagent:
12.0g of CH₄ × (1 mol of CH₄/16g CH₄) × (1 mole of CO₂/1 mole of CH₄) × (44g CO₂/1 mole of CO₂)
= 33g of CO₂
2. <u><em>Percent yield:</em></u>
= Actual yield/Theoretical yield × 100
= 22.0g/33g × 100
= 66.7%
Learn more about the percent yield here,
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Whenever objects are placed in a line with spaced in between them, the number of spaces is one less than the number of objects. For reference, you may hold up four fingers and count the spaced between your fingers.
Therefore, if there are 105 molecules, then there are 104 spaces present.
We also know that 1 mm = 1000 nm. So, we first convert the spacing to millimeters as the final answer is required in millimeters
spacing = 10.59/1000 = 0.01059 mm
Now, the width of the lattice will be (ignoring the size of the molecules):
104 * 0.01059
1.10 millimeters
The formula on the periodate table is Rb
Answer: 127 (3.s.f)
Explanation:
Boyle's law states that Volume x pressure = constant
Therefore let's first find the constant: 45 x 1900 = 85500
Then lets plug 675 ml and 85500 into the equation above:
675 x C = 85500
C = 127 (3 s.f.)
