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Tema [17]
3 years ago
10

Use the commutative property for addition to rearrange the algebraic expression 5x-7y-8x+y

Mathematics
1 answer:
BartSMP [9]3 years ago
5 0

You want to use the addition property, so you need to ADD each term. Just change the minuses to pluses, making sure you keep the negative with the number


5x-8x-7y+y =

5x + -8x + -7y +y

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What is the measure of (3y + 27)<br> What is the measure of (5y - 3)
saw5 [17]

Answer:

Angle A: 72°

Angle B: 108°

Step-by-step explanation:

Opposite angles are equal

Adjacent angles add up to 180

5y - 3 = 3y + 27

2y = 30

y = 15

Angle A:

5(15) - 3 = 72°

Angle B:

180 - 72 = 108°

4 0
3 years ago
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Mr. Lobo is building a France around his rectangular yard. It is 16 feet long and 14 feet wide. How many feet of fencing will he
Bess [88]
16*14=224 ft 2
i believe this is right
6 0
3 years ago
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Fractionsss helppp me pleeeeease
Setler [38]

Answer:

0.06

-0.35

0

-2.916

Step-by-step explanation:

8 0
3 years ago
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In a rhombus MPKN with an obtuse angle K the diagonals intersect each other at point E. The measure of one of the angles of a ∆P
allsm [11]
The rhombus has a couple of very interesting properties. The first is that the diagonals meet at 90o angles.

The second is that all the sides are congruent. That's actually the key to the problem (or one of them.

The third is that the diagonals are line segments that bisect the angles where the vertex of the angle is. 

So just to make sure you understand what that last statement means <PKM  =  <NKM
K is the vertex of angle PKN 

Now the really heavy duty stuff about your question.
Given
K is obtuse. Therefore <PKM can't be 16o because MKN would also have to be 16 degrees and together they don't add up to anything over 90o.
So the 16o angle is at <EPK

Remember that the diagonals meet at right angles. <PEK = 90o

Finally all triangles have 180o
< PKE = 180 - 16 - 90 = 74. So to review
<PKE = 74o
<EPK = 16o
<PEK = 90o That's one half the problem.

Moving on to triangle PMN
By the properties of parallel lines and a rhombus  and isosceles triangles, that since PKN is bisected (rhombus property) Then PKN = 2* PKM =2*74 = 148o
The angle opposite <PKN is equal to <PKN so <PMN = <PKN
Since PKN = 148 then PMN = 148
Since KPN = 16o then PMN = 16o
Since triangle <PMN is isosceles <PNM = 16o

Summing up 
PMN = 148o
MPN = 16o
MNP = 16o

That's both triangles solved. This is a really nice little problem. If you google properties of a rhombus, you will find all the properties I have used proven. 
 
5 0
3 years ago
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One weekend, 600 tickets were sold to a carnival for a total of $2400. If an adult's ticket costs $6 and a child's ticket costs
erastovalidia [21]

Answer:

adults : 0  children: 600

Step-by-step explanation:

x + y = 600

6x+4y = 2400

4×(x + y = 600) = 4x+4y = 2400

(6x+4y = 2400) - (4x+4y = 2400) = x=0

so y=600

8 0
2 years ago
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