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Evgen [1.6K]
3 years ago
7

Which of the following is not a simple machine

Chemistry
1 answer:
dedylja [7]3 years ago
5 0
C: screw I believe so
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The atoms of liquid Mercury are
KATRIN_1 [288]
Mercury atoms have 80 electrons and 80 protons with 122 neutrons in the most abundant isotope. Under standard conditions mercury is a shiny, heavy, silvery liquid. It is the only metal that is liquid at room temper
3 0
4 years ago
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A 100g of sample of a compound is combusted in excess oxygen and the products are 2.492g of CO2 and 0.6495 of H2O. Determine the
ruslelena [56]

The empirical formula : C₁₁O₁₄O₃

<h3>Further explanation</h3>

The assumption of the compound consists of C, H, and O

mass of C in CO₂ =

\tt \dfrac{12}{44}\times 2.492=0.680~g

mass of H in H₂O =

\tt \dfrac{2.1}{18}\times 0.6495=0.072~g

mass of O :

mass sample-(mass C + mass H)

\tt 1-(0.68+0.072)=0.248`g

mol of  C :

\tt \dfrac{0.68}{12}=0.056

mol of H :

\tt \dfrac{0.072}{1}=0.072

mol of O :

\tt \dfrac{0.248}{16}=0.0155

divide by 0.0155(the lowest ratio)

C : H : O ⇒

\tt \dfrac{0.056}{0.0155}\div \dfrac{0.072}{0.0155}\div \dfrac{0.0155}{0.0155}=3.6\div 4.6\div  1\\\\\dfrac{11}{3}\div \dfrac{14}{3}\div \dfrac{3}{3}=11:14:3

3 0
3 years ago
The neutralization of a 0.455 g sample of recrystallized aspirin required 38.6 mL of 0.100 M NaOH solution. An additional 25.0 m
Schach [20]

Answer:

E) Two of the above statements are true.

Explanation:

The options are:

A) Before the solution is titrated with HCl it is pink and when the color changes from pink to colorless, the moles of H*(aq) equals the moles of OH"(aq) used in the hydrolysis of the neutralized aspirin. <em>TRUE. </em>Before the solution is titrated, there is an excess of NaOH (Basic solution, phenolphtalein is pink). Then, at equivalence point, after the addition of HCl, the pH is acidic and phenolphtalein is colorless.

B) Before the solution is titrated with HCl it is colorless and when the color changes from colorless to pink, the moles of H*(aq) equals the excess moles of OH(aq) added. <em>FALSE. </em>As was explained, before the titration, the solution is pink.

C) 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The titration with HCl allows us to determine the moles of excess OH(aq) added. Once we determine the moles of excess OH(aq), we can determine moles of OH"(aq) used in the hydrolysis of the neutralized aspirin, which is equal to the moles of aspirin in the recrystallized aspirin. <em>TRUE. </em>Aspirin requires an excess of base (NaOH) for a complete dissolution (Hydrolysis). Then, we add H+ as HCl to know the excess moles of OH-. As we know the added moles of OH-, we can find the moles of OH that reacted = Moles of aspirin.  

D) We can determine the moles of aspirin in the recrystallized aspirin by titrating with the 0.100 M NaOH to the neutralization point. The purpose of the hydrolysis of the neutralized aspirin and the back-titration with the 0.100 M HCl is to confirm the moles of aspirin in the recrystallized aspirin. <em>FALSE. </em>NaOH can be added directly unyil neutralization point because, initially, aspirin can't be dissolved completely

E) Two of the above statements are true. <em>TRUE</em>

<em></em>

Right option is:

<h3>E) Two of the above statements are true.</h3>
3 0
3 years ago
I need yall help with this one and i can make yall brilientist if u get it right plus yall get 50 points
mixas84 [53]

Answer:

D

Explanation:

6 0
3 years ago
Read 2 more answers
For the chemical reaction HCN ( aq ) + KOH ( aq ) ⟶ H 2 O ( l ) + KCN ( aq ) HCN(aq)+KOH(aq)⟶H2O(l)+KCN(aq) write the net ionic
Anna11 [10]

Answer:

H+(aq)   + OH-(aq) ⟶H2O(l)

Explanation:

Step 1: The balanced equation

HCN(aq) + KOH(aq) ⟶ H2O (l) + KCN (aq)

H+(aq) + CN-(aq) + K+(aq) + OH-(aq) ⟶H2O(l) + K+(aq) + CN-(aq)

Step 2: The net ionic equation

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:

H+(aq)   + OH-(aq) ⟶H2O(l)

4 0
4 years ago
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