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defon
3 years ago
6

Which feature of a longitudinal wave corresponds to a trough in a transverse wave?

Physics
2 answers:
Tanya [424]3 years ago
5 0

Answer:

Crest

Explanation:

The crest is the peak at the top of the wave which peaks at the top of the wave on the longitudinal wave. Compared to a trough in a transverse wave, where it is the lowest point in the wave where the medium is at it lowest.

Therefore, they correspond

Hope this helps :)

Have a nice day!

Rama09 [41]3 years ago
3 0
It’s the crest, the crest is the top part of the wave and the trough is the bottom so they correspond
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Using the projectiles equations for y and x at what second does the ball have a vertical velocity of -39.2 m/s^2
vovangra [49]

Answer:

<h2>a) t = 4</h2>

Explanation:

In projectile the time taken by an object to reach its maximum height is the maximum time (tmax).

tmax = Usin\theta/g

U = velocity of the ball

\theta = angle of projection = 90° (vertical velocity)

g = acceleration due to gravity = 9.8m/s²

tmax = Usin90°/9.8

tmax = U/9.8

T the maximum height U = Uy =  39.2 m/s²

tmax = 39.2/9.8

tmax = 4secs

To calculate the time at which the ball will have an horizontal velocity, we will use the same formula but \theta will be 0° in this case

If Ux = Ucos\theta

8 = Ucos0

U = 8m/s

Since t = Usin\theta/g

t = 8sin0/9.8

t = 0sec

8 0
3 years ago
Two students who live on planet X. They want to estimate the circumference. The two students synchronize their watches before on
dexar [7]

Answer:

72000 miles

Explanation:

If the distance between the students is 600 miles, and this implies in a 3 degree difference in the sun position, that means this 600 miles is related to 3 degrees of the circunference of the planet.

So, to find the whole circunference of the planet, that is, 360 degrees, we just need to use a rule of three:

3 degrees -> 600 miles

360 degrees -> x miles

3x = 600 * 360

x = 600 * 360 / 3 = 72000 miles

7 0
3 years ago
Suppose that the electric field in the Earth's atmosphere is E = 1.16 102 N/C, pointing downward. Determine the electric charge
butalik [34]

Answer:

Electric charge in the earth will be Q=5.231\times 10^5C

Explanation:

We have given that E = 116 N/C

Radius of the earth R = 6371 km = 6371000 m

We have to find the electric charge in the earth '

We know that electric field due to charge is given by E=\frac{1}{4\pi \epsilon _0}\frac{Q}{R^20}=\frac{KQ}{R^2}. here K is coulomb's constant

So  116=\frac{9\times 10^9\times Q}{(6371000)^2}

Q=5.231\times 10^5C

So electric charge in the earth will be Q=5.231\times 10^5C

5 0
3 years ago
A 15kg projectile is moving with a velocity of 25m/s calculate its momentum
aliina [53]

The momentum of an object is given by:

p = mv

m is the object's mass and v is its velocity.

Given values:

m = 15kg

v = 25m/s

Plug in the values and solve for p:

p = 15*25

p = 375kg×m/s

8 0
4 years ago
The de Broglie wavelength of an electron traveling at 7.0 x 107m/s is 1.0 x 10-11m. (Remember that me = 9.1 x 10-31kg and h = 6.
ivolga24 [154]

The De Broglie's wavelength of a particle is given by:

\lambda=\frac{h}{p}

where

h=6.6 \cdot 10^{-34} Js is the Planck constant

p is the momentum of the particle


In this problem, the momentum of the electron is equal to the product between its mass and its speed:

p=m_e v=(9.1 \cdot 10^{-31} kg)(7.0 \cdot 10^7 m/s)=6.4 \cdot 10^{-23} kg m/s

and if we substitute this into the previous equation, we find the De Broglie wavelength of the electron:

\lambda=\frac{h}{p}=\frac{6.6 \cdot 10^{-34} Js}{6.4 \cdot 10^{-23} kg m/s}=1.0 \cdot 10^{-11} m


So, the answer is True.

7 0
3 years ago
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