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Trava [24]
3 years ago
11

An iron atom (Fe) has 26 protons in it. If the atom has 20 electrons in it, explain what type of charge it has and how you can t

ell.
Physics
1 answer:
gogolik [260]3 years ago
4 0

Answer:

The iron atom has a positive charge, making it a cation.

Explanation:

The atom has a nucleus, where the protons and neutrons, which are the subatomic particles with the highest mass, are located. Practically all the mass of the atom is concentrated in the nucleus.Protons have a positive electrical charge, while neutrons have no charge.

Electrons move around the nucleus with other negatively charged particles.

An iron atom (Fe) has 26 protons and 20 electrons in it.  That is, there are 6 more protons than electrons. As mentioned, protons are positively charged. So <u><em>the iron atom has a positive charge, making it a cation</em></u>.

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Sound travels through air at 343 m/s,
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The sound wave will have traveled 2565 m  farther in water than in air.

Answer:

Explanation:

It is known that distance covered by any object is directly proportional to the velocity of the object and the time taken to cover that distance.

Distance = Velocity × Time.

So if time is kept constant, then the distance covered by a wave can vary depending on the velocity of the wave.

As we can see in the present case, the velocity of sound wave in air is 343 m/s. So in 2.25 s, the sound wave will be able to cover the distance as shown below.

Distance = 343 × 2.25 =771.75 m

And for the sound wave travelling in fresh water, the velocity is given as 1483 m/s. So in a time interval of 2.25 s, the distance can be determined as the product of velocity and time.

Distance = 1483×2.25=3337 m.

Since, the velocity of sound wave travelling in fresh water is greater than the sound wave travelling in air, the distance traveled by sound wave in fresh water will be greater.

Difference in distance covered in water and air = 3337-772 m = 2565 m

So the sound wave will have traveled 2565 m  farther in water than in air.

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3 years ago
Refer to science 10 (mirror mirror on the wall)how do the height and width of the object compare with the height and width of th
Irina-Kira [14]

Depends on what type of mirror that is. I am going to assume this is a plain mirror (from the phrase), which means the height and width of the object and image is exactly the same.

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How do air quality scientists ensure the air is cleaned? What steps do they take?
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Air sample of places around the world compared to clean air
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Device based on atmospheric pressure​
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8 0
2 years ago
2. (9 points) A car starts from 10 mph and accelerates along a level road, i.e., no grade change. At 500 ft from its starting po
Sonja [21]

Answer:

a) t = 11.2 s

b) v = 70.5 mph

Explanation:

a)

  • Since we need to find the time, we could use the definition of acceleration (rearranging terms) as follows:

       t = \frac{v_{f} - v_{o}}{a}  (1)

  • where vf = 50 mph, and v₀ = 10 mph.
  • However, we still lack the value of a.
  • Assuming that the acceleration is constant, we can use the following kinematic equation:

       v_{f} ^{2} - v_{o} ^{2} = 2*a* \Delta x  (2)

  • Since we know that Δx = 500 ft, we could solve (2) for a.
  • In order to simplify things, let's first to convert v₀ and vf from mph to m/s, as follows:

       v_{o} = 10 mph*\frac{1609m}{1mi} *\frac{1h}{3600s} = 4.5 m/s  (3)

       v_{f} = 50 mph*\frac{1609m}{1mi} *\frac{1h}{3600s} = 22.5 m/s  (4)

  • We can do the same process with Δx, from ft to m, as follows:

       \Delta x = 500 ft *\frac{0.3048m}{1ft} = 152.4 m  (5)

  • Replacing (3), (4), and (5) in (2) and solving for a, we get:

       a = \frac{v_{f} ^{2} - v_{o}^{2}}{2*\Delta x} =  \frac{(22.5m/s) ^{2} - (4.5m/s)^{2}}{2*152.4m}  = 1.6 m/s2  (6)

  • Replacing (6) in (1) we finally get the value of the time t:

        t = \frac{v_{f} - v_{o}}{a} =  \frac{(22.5m/s) - (4.5m/s)}{1,6m/s2}  = 11.2 s  (7)

b)

  • Since the acceleration is constant, as we know the displacement is another 500 ft (152.4m), if we replace in (2) v₀ by the vf we got in a), we can find the new value of vf, as follows:

       v_{f} = \sqrt{v_{o} ^{2} +( 2*a* \Delta x)} = \sqrt{(22.5m/s)^{2} + (2*1.6m/s2*152.4m)} \\ v_{f} = 31.5 m/s (8)

  • If we convert vf again to mph, we have:

       v_{f} = 31.5m/s*\frac{1mi}{1609m} *\frac{3600s}{1h} = 70.5 mph  (9)

4 0
3 years ago
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