Answer:
The correct option is H
Explanation:
From the question we are told that
The index of refraction of coating is
The index of refraction of material is 
Generally the condition for constructive for a thin film interference is mathematically represented
![2 * t = [ m + \frac{1}{2}] \frac{\lambda}{n_1 }](https://tex.z-dn.net/?f=2%20%2A%20%20t%20%20%3D%20%5B%20m%20%20%2B%20%5Cfrac%7B1%7D%7B2%7D%5D%20%5Cfrac%7B%5Clambda%7D%7Bn_1%20%7D)
Here t represents the thickness
For minimum thickness m = 0
So

=> 
Answer:
28 degree C
Explanation:
We are given that




We have to find the temperature on a spring day when resistance is 215.1 ohm.
We know that

Using the formula




Hence, the temperature on a spring day 28 degree C.
Answer:
(A) ratio of electric force to weight will be 
(b) Electric field will be 
Explanation:
We have given mass of bee = 100 mg = 
Charge on bee 
Electric field E = 100 N/C
Weight of the bee 
Electric force on the bee 
So the ratio of electric force on the bee and weight is 
(B) To hold the bee in air electric force must be equal to weight of bee
So 


Answer:
Moving a unit "positive" test charge from A to B will result in a reduction in potential
V = K Q / R potential at a point
V2 - V1 = K Q (1 / .4 - 1 / .15) = = k Q (.15 - .4) / .06 = -4.17 K Q
V2 - V1 = -4.17 * 9 & 10E9 * 6.25 E-8
V2 - V1 = -4.17 * 562.5 J/C
V = - 2346 Volts