Answer:
According to Hund's rule and the Aufbau principle in which the orbitals must be filled with electrons, they are not strictly applied in the real universe, because the intermediate and electron-filled atomic orbitals are very stable . Because there are four d-orbitals in universe L, a typical half-full configuration will be xd4 and its full configuration will be xd8, where x is the primary orbital for any specific element. Here is an example:
Vahadium ₂₃V
in real universe: [Ar]₈ 3d³4s²
in universe L: [Ar]₁₈ 3d⁴4s¹
Chromium
in real universe: [Ar]₈ 3d⁵4s¹
in universe L: [Ar]₁₈ 3d⁴4s²
Explanation:
Answer:
Approximately
.
Explanation:

The actual yield of
was given. The theoretical yield needs to be calculated from the quantity of the reactant.
Balance the equation for the hydrolysis of water:
.
Note the ratio between the coefficient of
and
:
.
This ratio will be useful for finding the theoretical yield of
.
Look up the relative atomic mass of hydrogen and oxygen on a modern periodic table.
Calculate the formula mass of
and
:
.
.
Calculate the number of moles of molecules in
of
:
.
Make use of the ratio
to find the theoretical yield of
(in terms of number of moles of molecules.)
.
Calculate the mass of that approximately
of
(theoretical yield.)
.
That would correspond to the theoretical yield of
(in term of the mass of the product.)
Given that the actual yield is
, calculate the percentage yield:
.
Answer:
For your first question, Curium does not occur naturally on Earth, meaning that it is not produced naturally on Earth. However, it can be formed in nuclear reactors.
For your second question, Curium has been used to provide power to electrical equipment used on space missions, but doesn't seem to be that important overall.
Explanation:
Hope this helped!
Answer:
HCl
Explanation:
The best solvent for NaF is a polar liquid. The only liquid having a significant dipole moment among the options is HCl due to the large electro negativity difference between hydrogen and chlorine.
The polar solvent can interact with the NaF via its dipoles such that the NaF dissolves due to ion-dipole interaction.
Answer:
Lithium does form a peroxide as well as an oxide on burning in air and I suspect the low temperature reaction with air forms a significant amount of peroxide.