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kotegsom [21]
2 years ago
13

Caffeine (C_8H_10N_4O_2) is a weak base with a K_b value of 4 times 10^-4. The pH of a 0.01 M solution of caffeine is in the ran

ge of: a. 2-3 b. 5-6 c. 7-8 d. 9-10 e. 11-12
Chemistry
1 answer:
docker41 [41]2 years ago
3 0

Answer:

The pH of the solution lies from 11 to 12.Hence, option e is correct.

Explanation:

The value of K_b for caffine = 4\times 10^{-4}

CafOH(aq)\rightleftharpoons Caf(aq)+OH^-(aq)

Initial

   0           0.01 M       0

AT equilibrium:

  x          (0.01 -x)M      x

K_b=\frac{x(0.01-x)}{(x)}

4\times 10^{-4}=\frac{x(0.01-x)}{(x)}

Solving for x:

x = 0.0096 M

The pOH of the solution is given by :

pOH=-\log[OH^-}

pOH=-\log[x]

pOH=-\log[0.0096]

pOH = 2.02

pH= 14 - pOH = 14 - 2.02 = 11.98

The pH of the solution lies from 11 to 12.

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