Answer : The heat capacity (calorimeter constant) of the calorimeter is,
Explanation:
First we have to calculate the moles of compound A.
Now we have to calculate the heat of combustion of compound A for 0.01224 mol.
As, 1 mole of compound A has heat of combustion = 3568.0 kJ
So, 0.01224 mole of compound A has heat of combustion = 0.01224 × 3568.0 kJ
= 43.67 kJ
Now we have to calculate the heat capacity (calorimeter constant) of the calorimeter.
where,
q = heat of combustion = 43.67 kJ
c = heat capacity = ?
= change in temperature =
Now put all the given values in the above expression, we get:
Therefore, the heat capacity (calorimeter constant) of the calorimeter is,