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Degger [83]
2 years ago
9

How much Gravitational Potential Energy does a 1.48 kg book at rest on top of a 2.4 m tall desk have?

Physics
1 answer:
Naily [24]2 years ago
4 0

Gravitational Potential Energy GPE = mg∆h. 12. A 5.0 kg mass is initially sitting on the floor when it is lifted onto a table 1.15 meters high at.

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Describe how substance move from one state to another
Mekhanik [1.2K]
The temperature rises until the water reaches the next change of state — boiling. As the particles move faster and faster, they begin to break the attractive forces between each otherand move freely as steam — a gas. The process by which a substance moves from the liquid state to the gaseousstate is called boiling.
4 0
3 years ago
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Match the sentences in Column A based on whether they describe radio waves, visible light waves, or both (Column B). Column A 1.
Andrew [12]
<span>1. They’re invisible - RADIO WAVES

2. They have colors. - VISIBLE LIGHT WAVES

3. They’re used to learn about dust and gas clouds. - BOTH

4. They can travel in a vacuum. </span> - BOTH<span>

5. They’re used to find the temperature of stars. </span>- VISIBLE LIGHT WAVES<span>

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8 0
2 years ago
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The brakes on your automobile are capable of creating a deceleration of 4.6 m/s^2. If you are going 114 km/h and suddenly see a
drek231 [11]

Answer:

The minimum time to get the car under max. speed limit of 79 km/h is 2.11 seconds.

Explanation:

a=\frac{V_f-V_0}{t}

isolating "t" from this equation:

t=\frac{V_f-V_0}{a}

Where:

a=-4.6m/s^2 (negative because is decelerating)

V_f= 79 km/h

V_0= 114 km/h

First we must convert velocity from km/h to m/s to be consistent with units.

79\frac{km}{h}*\frac{1000m}{1 km}*\frac{1h}{3600s}=\frac{79*1000}{3600}=21.94 m/s

114\frac{km}{h}*\frac{1000m}{1 km}*\frac{1h}{3600s}=\frac{114*1000}{3600}=31.67 m/s

So;

t=\frac{V_f-V_0}{a}=\frac{21.94 m/s-31.66m/s}{-4.6 m/s^2}=2.11 s

7 0
3 years ago
What happens to light when it strikes the inside surface of a smooth, curved mirror? It bounces in random directions. It bounces
kotykmax [81]
This is a concave mirror you're talking about, so all of the points are going to converge to a single focal point. Therefore the answer would be that it bounces back toward a single spot
5 0
3 years ago
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PLLLLLLZ HELP 15 POINTS
amid [387]
<h2>Option A is the correct answer.</h2>

Explanation:

A 10-ω resistor and a 30-ω resistor are connected in series across a 100-V battery

Total resistance = 10 + 30 = 40 ω

We have

            Voltage = Current x resistance

            100 = I x 40

              I = 2.5 A

In series current in all the resistors are same, that is 2.5 A

             Voltage in 10ω resistor, V = I x 10 = 2.5 x 10 = 25 V

In parallel connection potential in all the resistors are same.

             Voltage in 10ω resistor, V = 100 V

The ratio of the potential difference across the 10-ω resistor in the series combination to that of the 10-ω resistance connected in parallel = 25/100 = 1/4

Option A is the correct answer.

8 0
3 years ago
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