0.36 J of work is done in stretching the spring from 15 cm to 18 cm.
To find the correct answer, we need to know about the work done to strech a string.
<h3>What is the work required to strech a string?</h3>
- Mathematically, the work done to strech a string is given as 1/2 ×K×x².
- K is the spring constant.
<h3>What will be the spring constant, if 40N force is required to hold a 10 cm to 15 cm streched spring?</h3>
- The force experienced by a streched spring is given as Kx. x is the length of the spring streched from its natural length.
- Then K = Force / x.
- Here x = 15 - 10 = 5 cm = 0.05 m
- K = 40/0.05 = 800N/m.
<h3>What will be the work required to strech that spring from 15 cm to 18 cm?</h3>
- Work done = 1/2×k×x²
- Here x= 18-15=3cm or 0.03 m
- So, W= 1/2×800×0.03² = 0.36 J.
Thus, we can conclude that the work done is 0.36 J.
Learn more about the spring force here:
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Answer:
You have to give us an answer choice : )
Answer:
Explanation:
Given that,
Electric Field is
E = 650 N/C
The potential at x1 = 3 is
V1 = 1700V
What is the potential at x2 = 1
V2 =?
Electric potential is given as
V = Ed
Then,
E = V/d
Therefore, the electric field is gradient of the potential and the position.
So,
E = —∆V / ∆x
E = — (V2 — V1) / (x2 — x1)
E = —(V2—1700) / (1—3)
650 = — ( V2—1700) / -2
650 × -2 = —V2 + 1700
-1300 = -V2 + 1700
V2 = 1700+1300
V2 = 3000 V
Answer:
Work:
Hope this helps you. Kinematics can be tricky, but I'm sure you'll get a good grip on it. Have a good night.
