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NNADVOKAT [17]
3 years ago
6

PLEASE HELP ASAP!!!!!!!!

Chemistry
1 answer:
Step2247 [10]3 years ago
3 0

Answer:

1).There are 6.87 x 1023 atoms in 1.14 mol SO3, or sulfur trioxide (mol is the abbreviation for mole)

2).6.022*1023 R.P . is equal to 144

3)7.02 g Si

4)104*10 raised to 1

5)idk

6)142.04 g/mol

7)atom

8) idk

Explanation:

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BRAINLIESTTT ASAP!!! PLEASE HELP ME :)
Leno4ka [110]

Answer:

"Thermometer C, because it measures accurately in the ones place."

Explanation:

Thermometer D measures using tens place. Since we are measuring the liquid's temperature at 47 degrees Celsius, the most appropriate thermometer would measure in ones place, not tens place.

Hope this helps! :)

8 0
4 years ago
HELP ASAP PLZ
Luba_88 [7]

D. The total number of atoms when glucose and oxygen react stays the same when carbon dioxide and water are produced. The conservation of the mass is a fundamental law of chemistry and physics. It indicates not only that during any experiment, including if it involves a chemical transformation, the mass is conserved, but also that the number of elements of each chemical species is conserved. Like any law of conservation it is expressed by a conservation equation.

4 0
3 years ago
Read 2 more answers
Which of the following example(s) from everyday life are made possible by modern chemistry?
lorasvet [3.4K]

Answer:

I believe it is c

Explanation:

........................

7 0
3 years ago
Read 2 more answers
Combustion analysis is performed on 0.50 g of a hydrocarbon, and 1.47 g of CO2 and 0.902 g of H2O are produced. What is the empi
JulijaS [17]

1. The empirical formula of the hydrocarbon is CH₃

2. The molecular formula of the hydrocarbon is C₂H₆

<h3>How to determine the mass of Carbon </h3>
  • Mass of CO₂ = 1.47 g
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
  • Mass of C =?

Mass of C = (12 / 44) × 1.47

Mass of C = 0.4 g

<h3>How to determine the mass of H</h3>
  • Mass of compound = 0.5 g
  • Mass of C = 0.4 g
  • Mass of H = ?

Mass of H = (mass of compound) – (mass of C)

Mass of H = 0.5 – 0.4

Mass of H =0.1 g

<h3>1. How to determine the empirical formula </h3>
  • C = 0.4 g
  • H = 0.1 g
  • Empirical formula =?

Divide by their molar mass

C = 0.4 / 12 = 0.03

H = 0.1 / 1 = 0.1

Divide by the smallest

C = 0.03 / 0.03 = 1

H = 0.1 / 0.03 = 3

Thus, the empirical formula of the compound is CH₃

<h3>2. How to determine the molecular formula</h3>
  • Empirical formula = CH₃
  • Molar mass = 30 g/mol
  • Molecular formula =?

Molecular formula = empirical × n = mass number

[CH₃]n = 30

[12 + (3×1)]n = 30

15n = 30

Divide both side by 15

n = 30 / 15

n = 2

Molecular formula = [CH₃]n

Molecular formula = [CH₃]₂

Molecular formula = C₂H₆

Learn more about empirical formula:

brainly.com/question/24297883

#SPJ1

4 0
2 years ago
Select all steps below that you followed to practice laboratory safety during the experiment. used tongs or a test tube holder t
uysha [10]

Explanation:

Steps followed to practice laboratory safety during the experiment are as follows.

  • Used tongs or a test tube holder to hold materials over the Bunsen burner flame.
  • Wore gloves and goggles.
  • Made careful observations of the products and reactants.
  • Did not smell the gases produced.

When we heat a test tube over bunsen flame then the tube gets hot and when we hold it with bare hands then out hands will burn. Therefore, it is advised to hold test tube with the help of tongs or a holder so that our hands did not burn.

We should also wear gloves and goggles so that any acid would not spill directly on our hands, skin and eyes as it can affect or damage the skin severely.

Careful observations were made so that correct calculations about the experiment can be carried out.

It is also advised that we should not smell the gases produced but gases move freely from one place to another in a laboratory or any where else.

So, we can try to avoid it by covering our mouth with a cloth but we cannot stop it. If we keep on inhaling the gases produced in a laboratory then it can also lead to severe disease or defect in the human body.

8 0
3 years ago
Read 2 more answers
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