![A)F_0d](https://tex.z-dn.net/?f=A%29F_0d)
Explanation
If you graph the force on an object as a function of the position of that object, then the area under the curve will equal the work done on that object, so we need to find the area under the function to find the work
Step 1
find the area under the function.
so
Area:
![\text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red}](https://tex.z-dn.net/?f=%5Ctext%7BArea%7D%3Drec%5Ctan%20gle_%7Bgreen%7D%2Btriangle_%7Bgren%7D-triangle_%7Bred%7D)
![\begin{gathered} \text{the area of a rectangle is given by} \\ A_{rec}=lenght\cdot widht \\ \text{and} \\ \text{the area of a triangle is given by:} \\ A_{tr}=\frac{base\cdot height}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7Bthe%20area%20of%20a%20rectangle%20is%20given%20by%7D%20%5C%5C%20A_%7Brec%7D%3Dlenght%5Ccdot%20widht%20%5C%5C%20%5Ctext%7Band%7D%20%5C%5C%20%5Ctext%7Bthe%20area%20of%20a%20triangle%20is%20given%20by%3A%7D%20%5C%5C%20A_%7Btr%7D%3D%5Cfrac%7Bbase%5Ccdot%20height%7D%7B2%7D%20%5Cend%7Bgathered%7D)
so
![\begin{gathered} \text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red} \\ \text{replace} \\ \text{Area}=(F_0\cdot d)+\frac{(F_0\cdot d)}{2}-\frac{(F_0\cdot d)}{2} \\ \text{Area}=(F_0\cdot d) \\ Area=F_0d \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BArea%7D%3Drec%5Ctan%20gle_%7Bgreen%7D%2Btriangle_%7Bgren%7D-triangle_%7Bred%7D%20%5C%5C%20%5Ctext%7Breplace%7D%20%5C%5C%20%5Ctext%7BArea%7D%3D%28F_0%5Ccdot%20d%29%2B%5Cfrac%7B%28F_0%5Ccdot%20d%29%7D%7B2%7D-%5Cfrac%7B%28F_0%5Ccdot%20d%29%7D%7B2%7D%20%5C%5C%20%5Ctext%7BArea%7D%3D%28F_0%5Ccdot%20d%29%20%5C%5C%20Area%3DF_0d%20%5Cend%7Bgathered%7D)
therefore, the answer is
![A)F_0d](https://tex.z-dn.net/?f=A%29F_0d)
I hope this helps you
Answer:
Reflective
Explanation:
The radiation pressure of the wave that totally absorbed is given by;
![P_{abs}= \frac{I}{C}](https://tex.z-dn.net/?f=P_%7Babs%7D%3D%20%5Cfrac%7BI%7D%7BC%7D)
and While the radiation pressure of the wave totally reflected is given by;
![P_{ref}= \frac{2I}{C}](https://tex.z-dn.net/?f=P_%7Bref%7D%3D%20%5Cfrac%7B2I%7D%7BC%7D)
Now compare the two-equation you can clearly see that the pressure due to reflection is larger than absorption therefore the sail should be reflective.
Uhhhhhhhhh just tryna get a point so I can ask a question so eh I’m using ur question heheheheheh
Answer:
Conservation of angular momentum
Explanation:
When the objects spread in universe after big bang, because of the tremendous force , they gained angular momentum and started to rotate. Since, then the object continue to rotate on their axis because of conservation of angular momentum. In vacuum of space there no other forces that can stop these rotation, therefore, they continue to rotate.
Answer:
The fundamental frequency of can is 2.7 kHz.
Explanation:
Given that,
A typical length for the auditory canal in an adult is about 3.1 cm, l = 3.1 cm
The speed of sound is, v = 336 m/s
We need to find the fundamental frequency of the canal. For a tube open at only one end, the fundamental frequency is given by :
![f=\dfrac{v}{4l}\\\\f=\dfrac{336}{4\times 3.1\times 10^{-2}}\\\\f=2709.67\ Hz\\\\f=2.7\ kHz](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7Bv%7D%7B4l%7D%5C%5C%5C%5Cf%3D%5Cdfrac%7B336%7D%7B4%5Ctimes%203.1%5Ctimes%2010%5E%7B-2%7D%7D%5C%5C%5C%5Cf%3D2709.67%5C%20Hz%5C%5C%5C%5Cf%3D2.7%5C%20kHz)
So, the fundamental frequency of can is 2.7 kHz. Hence, this is the required solution.